What is the length of the hypotenuse of a right triangle if each of the two legs is 7 units? (1 point)
2 answers:
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>
Answer:
Square root of 98
Step-by-step explanation:
The Pythagorean Theorem states that a^2+b^2=c^2.
This means that the sides are represented by a^2+b^2. In order to find the hypotenuse in this problem, we substitute a and b for 7 and 7.
7^2+7^2=c^2
we do what it shows us and get:
49+49=c^2
from there, we add the left side altogether then square each side to get rid of the root.
98=c^2
√98=√c^2
and since 98 can't have two numbers that multiply together and be the same number, we leave it as is like this:
<u><em>√98 = c</em></u>
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Answer:
f=-552
/343 or 5=1 and 209/343
Step-by-step explanation:
Okay
(Thanks for the points)
Number one or 2? so i can help you
4 would be the answer for this questions
