Answer: d. 512
Step-by-step explanation:
You need to remember that:
![(\sqrt[3]{x})^3=x](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx%7D%29%5E3%3Dx)
Then, given the equation:
![\sqrt[3]{n}=8](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3D8)
You can find the value of "n" that make the equation true, by solving for "n".
So, to solve for "n", you need to raise both side of the equation to power 3. Therefore, you get:
![(\sqrt[3]{n})^3=(8)^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bn%7D%29%5E3%3D%288%29%5E3)
Then, the value of "n" that makes the equation true is: 512 (You can observe that this matches with the option d).
Answer: 255
Step-by-step explanation:
u = 10.4 and v = 12
Solution:
In the given 2 sides of a triangle are 60°, 60°.
Sum of all the angles of a triangle = 180°
60° + 60° + third angle = 180°
⇒ third angle = 180° – 60° – 60°
⇒ third angle = 60°
All angles are equal, therefore the given triangle is an equilateral triangle.
⇒ All sides are equal in length.
⇒ v = 12
The line drawn from the top angle divides the triangle into two equal parts
and the line is perpendicular.
12 ÷ 2 = 6
Using Pythagoras theorem,
⇒ 
⇒ 
⇒ 
⇒ 
⇒ u = 10.4
Hence, u = 10.4 and v = 12.
Answer:
B) 2
Below I wrote the steps on how I would find the answer.
Step-by-step explanation:
1. Yep, so basically cba = cbl + lba.
2. So you need to find x
3. So basically if you set up the equation 61x - 2 = 13x - 1 + 95
4. Then you can solve for x
5. X = 2
Let
A = event that the student is on the honor roll
B = event that the student has a part-time job
C = event that the student is on the honor roll and has a part-time job
We are given
P(A) = 0.40
P(B) = 0.60
P(C) = 0.22
note: P(C) = P(A and B)
We want to find out P(A|B) which is "the probability of getting event A given that we know event B is true". This is a conditional probability
P(A|B) = [P(A and B)]/P(B)
P(A|B) = P(C)/P(B)
P(A|B) = 0.22/0.6
P(A|B) = 0.3667 which is approximate
Convert this to a percentage to get roughly 36.67% and this rounds to 37%
Final Answer: 37%
