What is the value of COS H? Round to four decimal places if needed.
1 answer:
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The picture in the attached figure
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer is
m∠1 is 56.5°
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer is
m∠1 is 56.5°
Answer:
The first three nonzero terms in the Maclaurin series is
Step-by-step explanation:
GIven that:
The Maclaurin series of cos x can be expressed as :
From equation(1), substituting x with (4x), Then:
The first three terms of cos (4x) is:
Multiplying equation (2) with (3); we have :
Finally , multiplying 5 with ; we have:
The first three nonzero terms in the Maclaurin series is