Answer:
To ensure that they all have the equal amount of power; to make sure one branch doesn't have more power than the others.
Plot the equation. If you wish to solve a polynomial, let y= polynomial and plot the graph. Best set up a table of values first.
Where the graph crosses the x axis there is a solution for x. There are also solutions for other horizontal lines (y values) by looking at intersections of the graph with these lines. This technique works for linear and non linear equations. You can also use graphs to solve 2-variable systems of equations by examining where the graphs intersect one another. The disadvantage is that you may not be able to have sufficient detail for high degrees of accuracy because of the scale of the graph and drawing inaccuracies.
Answer:
A = 38°
B = 50.32°
C = 91.68°
a = 8
b = 10
c = 12.77
Step-by-step explanation:
The first thing is to find the angle B, like this:
sin B = b * sin A / a = 10 * sin (38 °) / 8
sin B = 0.77
B = arc sin (0.77)
B = 50.32 °
For angle C, it would be:
C = 180 - 38 - 50.32
C = 91.68 °
Side c, we calculate it like this:
c = a * sin C / sin A = 8 * sin (91.68 °) / sin (38 °)
c = 12.77
Because the lines are parallel, 75 is equal to 11x-2
75=11x-2
77=11x
x=7
1. cot(x)sec⁴(x) = cot(x) + 2tan(x) + tan(3x)
cot(x)sec⁴(x) cot(x)sec⁴(x)
0 = cos⁴(x) + 2cos⁴(x)tan²(x) - cos⁴(x)tan⁴(x)
0 = cos⁴(x)[1] + cos⁴(x)[2tan²(x)] + cos⁴(x)[tan⁴(x)]
0 = cos⁴(x)[1 + 2tan²(x) + tan⁴(x)]
0 = cos⁴(x)[1 + tan²(x) + tan²(x) + tan⁴(4)]
0 = cos⁴(x)[1(1) + 1(tan²(x)) + tan²(x)(1) + tan²(x)(tan²(x)]
0 = cos⁴(x)[1(1 + tan²(x)) + tan²(x)(1 + tan²(x))]
0 = cos⁴(x)(1 + tan²(x))(1 + tan²(x))
0 = cos⁴(x)(1 + tan²(x))²
0 = cos⁴(x) or 0 = (1 + tan²(x))²
⁴√0 = ⁴√cos⁴(x) or √0 = (√1 + tan²(x))²
0 = cos(x) or 0 = 1 + tan²(x)
cos⁻¹(0) = cos⁻¹(cos(x)) or -1 = tan²(x)
90 = x or √-1 = √tan²(x)
i = tan(x)
(No Solution)
2. sin(x)[tan(x)cos(x) - cot(x)cos(x)] = 1 - 2cos²(x)
sin(x)[sin(x) - cos(x)cot(x)] = 1 - cos²(x) - cos²(x)
sin(x)[sin(x)] - sin(x)[cos(x)cot(x)] = sin²(x) - cos²(x)
sin²(x) - cos²(x) = sin²(x) - cos²(x)
+ cos²(x) + cos²(x)
sin²(x) = sin²(x)
- sin²(x) - sin²(x)
0 = 0
3. 1 + sec²(x)sin²(x) = sec²(x)
sec²(x) sec²(x)
cos²(x) + sin²(x) = 1
cos²(x) = 1 - sin²(x)
√cos²(x) = √(1 - sin²(x))
cos(x) = √(1 - sin²(x))
cos⁻¹(cos(x)) = cos⁻¹(√1 - sin²(x))
x = 0
4. -tan²(x) + sec²(x) = 1
-1 -1
tan²(x) - sec²(x) = -1
tan²(x) = -1 + sec²
√tan²(x) = √(-1 + sec²(x))
tan(x) = √(-1 + sec²(x))
tan⁻¹(tan(x)) = tan⁻¹(√(-1 + sec²(x))
x = 0
