Answer:
57
Step-by-step explanation:
9+8(6)
9+48
57
The answer to this is n= 4
Answer:
b. even
Step-by-step explanation:
m is a multiple of 8, so it is also a multiple of 4. When a multiple of 4 is divided by 2, the result is a multiple of 2 (even).
Answer:
(a) The range of the function represents the set of values on the y-axis. We see that function has an absolute maximum, then the range of the function is:
![Ran\{f(x)\} = (-\infty, 4]](https://tex.z-dn.net/?f=Ran%5C%7Bf%28x%29%5C%7D%20%3D%20%28-%5Cinfty%2C%204%5D)
(b) The location of the maximum is represented by its ordered pair. After direct observation, we located this maximum at 
(c) By direct observation we find that the value of 
when 
is -12.
(d) By direct observation we conclude that the values of 
when 
are -4.8 and 2.
Step-by-step explanation:
(a) The range of the function represents the set of values on the y-axis. We see that function has an absolute maximum, then the range of the function is:
(b) The location of the maximum is represented by its ordered pair. After direct observation, we located this maximum at
(c) By direct observation we find that the value of when is -12.
(d) By direct observation we conclude that the values of when are -4.8 and 2.
Answer:
a. The first six terms are:
-7, -4, -1, 2, 5, 8
b. The first six terms are:
0, 2, 0, 2, 0, 2.
c. The first six terms are:
4, 8, 24, 96, 480, 2880
Step-by-step explanation:
a. an - 3n - 10
For n = 1
a1 = 3(1) - 10
= -7
For n = 2
a2 = 3(2) - 10
= -4
For n = 3
a3 = 3(3) - 10
= -1
For n = 4
a4 = 3(4) - 10
= 2
For n = 5
a5 = 3(5) - 10
= 5
For n = 6
a6 = 3(6) - 10
= 8
The first six terms are:
-7, -4, -1, 2, 5, 8
b. an= (1+(-1)^n)^n
For n = 1
a1 = (1+(-1)^1)^1
= 0
For n = 2
a2 = (1+(-1)^2)^1
= 2
For n = 3
a3 = (1+(-1)^3)^1
= 0
For n = 4
a4 = (1+(-1)^4)^1
= 2
For n = 5
a5 = (1+(-1)^5)^1
= 0
For n = 6
a6 = (1+(-1)^6)^1
= 2
The first six terms are:
0, 2, 0, 2, 0, 2.
c. an= 2n! (2)
For n = 1
a1 = 2(1!)(2)
= 4
For n = 2
a2 = 2(2!)(2)
= 8
For n = 3
a3 = 2(3!)(2)
= 24
For n = 4
a4 = 2(4!)(2)
= 96
For n = 5
a5 = 2(5!)(2)
= 480
For n = 6
a6 = 2(6!)(2)
= 2880
The first six terms are:
4, 8, 24, 96, 480, 2880
