Can anyone help me with this problem?

I need help on this question about percentages

Vera_Pavlovna [14]

Sales above monthly quota = 23800 - 17000 = $6800

So her commission = 0.05 * 6,800 = $340

Therefore her total salary for the month = 3600 + 340

= $3,940 (answer).

7 0

3 years ago

Read 2 more answers

I need help on the top one hellppp it’s due today

Digiron [165]

Answer:

.666666... lph, 22 lawns

Step-by-step explanation:

6/9 to get lawns per hour.

Take that fraction times 33 to get lawns in 33 hours.

7 0

3 years ago

Your lungs hold about 4.5 liters of air after you inhale and about 3.5 liters of air after you exhale. If you take 6 breaths eve

ser-zykov [4K]

Answer:

$A(t)=0.5cos(12\pi\cdot t)+4$

Step-by-step explanation:

Function Modeling

Since the air in the lungs goes periodically from a minimum value to a maximum value, we can simulate its behavior as a sinusoid. Selecting a sine or a cosine will depend on the initial condition we'll assume since the question doesn't provide one. We'll set the initial state when the lungs are at maximum air content. The sinusoid that starts from maximum is the cosine, so our model is

$A(t)=A_ocos(wt)+M$

Where Ao is the amplitude of the oscillation, w is the angular frequency and M is the midline or y-displacement of the wave.

The values of A run from a min of 3.5 to a max of 4.5. That gives us twice the amplitude, thus

$\displaystyle A_o=\frac{4.5-3.5}{2}=0.5$

The vertical displacement or midline can be found as the shift from the center value:

$\displaystyle M=\frac{4.5+3.5}{2}=4$

We also know the cycle repeats 6 times per minute. If the time is expressed in minutes, then the frequency is f=6

Knowing that

$w=2\pi f$

Then

$w=12\pi$

The model is

$\boxed{A(t)=0.5cos(12\pi\cdot t)+4}$

where t is expressed in minutes

7 0

3 years ago

PLEASE HELP ME!!! I WILL GIVE BRAINLEST PLEASE

dolphi86 [110]

Answer:

7

Step-by-step explanation:

you just multiply from the least and once you get to the greatest, it should be 7

3 0

2 years ago

A mass weighing 32 pounds stretches a spring 2 feet. Determine the amplitude and period of motion if the mass is initially relea

gulaghasi [49]

Answer:

Amplitude = 0.7183m

Period of motion (T) = 1.566 seconds

Step-by-step explanation:

First of all, lets convert all the figures given in the question to standard units for ease of calculations.

1 pound = 0.454kg. Therefore, 32 pounds = 32 x 0.454kg = 14.528kg

Mass(M) = 14.528kg

Velocity (v) = 5ft/s; now, 1ft/s = 0.305m/s; so 5ft/s = 5x0.305m/s = 1.524m/s

So v=1.524m/s

Change in length of spring (^x) = 2ft. If 1ft = 0.3048, 2ft = 2x0.3048 = 0.6096m

Now,we know that Weight = Mg where g = 9.81m/s^2

Therefore, W = 14.528 x 9.81 = 142.52N

Now, ^F is the same as weight and

^F = k(^x) where k is the spring constant. Therefore k = ^F/^x

K= 142.52/0.6096 = 233.79N/m

Angular speed (ω) = (k/m) ^(1/2)

Therefore, ω = (233/14.528)^(1/2)

ω = 16.093^(1/2) = 4.012 rad/s

It is well known that ω = 2πf ; where f is frequency.

Therefore, f = ω/2π ; f= 4.012/2π = 0.6385 hz.

Period of motion (T) = 1/f

So, T = 1/0.6385 = 1.566 seconds

From proven oscillation equations;

V^2 = ω^2 (A^2 - x^2) ; where v is velocity, and A is amplitude.

Therefore let's make A the subject of the the equation ;

(V^2/ω^2) + (x^2) = (A^2)

So, {(1.524^2)/(4.012^2)} + (0.6096^2) = (A^2)

So, (A^2) = 0.5159

So, A = 0.5159^(1/2) = 0.7183m

3 0

3 years ago