Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 
x - 6 ← is in slope- intercept form
with slope m =
Parallel lines have equal slopes , then
y = x + c ← is the partial equation
To find c substitute (9, 2) into the partial equation
2 = 6 + c ⇒ c = 2 - 6 = - 4
y = x - 4 ← equation of parallel line
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Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
= - 
, then
y = - x + c ← is the partial equation
To find c substitute (9, 2) into the partial equation
2 = - 
+ c ⇒ c = 2 + = 
y = - x + ← equation of perpendicular line
Answer:
ZSDFCVGBHNJMK
Step-by-step explanation:
From the diagram above,
XZ = 10 in and OX = 10 in
we are to find length of OY
XZ is a chord and line OY divides the chord into equal length
Hence, ZY=YX= 5 in
Now we solve the traingle OXY
To find OY we solve using pythagoras theorem
applying values from the triangle above
![\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20OX%5E2%3DXY%5E2%2BOY%5E2%20%5C%5C%2010%5E2%3D5%5E2%2BOY%5E2%20%5C%5C%20100%3D25%2BOY%5E2%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%20100%20-25%7D%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%2075%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B75%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B25%5Ctext%7B%20%7D%5Ctimes%5Ctext%7B%203%7D%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%205%7D%5Csqrt%5B%5D%7B3%5Ctext%7B%20%7D%7Din%20%5Cend%7Bgathered%7D)
Therefore,
Length of OY =
![5\sqrt[]{3}](https://tex.z-dn.net/?f=5%5Csqrt%5B%5D%7B3%7D)
Since it's either/or, we can simply add up 3/10 (0.3) and 1/5 (0.2) to get 0.5=1/2
Answer:
32 seconds
Step-by-step explanation:
For some number of seconds (s), Tess's essay length (t) will be ...
t = 42 +1.3s
and Margo's essay length (m) will be ...
m = 122 -1.2s
We will have t > m when ...
t > m
42 +1.3s > 122 -1.2s
2.5s > 80 . . . . . . . . add 1.2s-42
s > 32 . . . . . . . . . . . divide by 2.5
After 32 seconds, Tess's essay will exceed Margo's in length.
