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patriot [66]
3 years ago
12

Pls do answer correct for brainliest

Mathematics
2 answers:
olga55 [171]3 years ago
6 0

Answer:

3 \frac{1}{9}

PilotLPTM [1.2K]3 years ago
4 0

Answer:

3\frac{1}{9}

Step-by-step explanation:

First, make the denominator the same.

We will get 6 \frac{3}{9} - 3\frac{2}{9}.

Now, both denominators are both 9 and it's easier to calculate this way.

Subtract: 6\frac{3}{9} -3\frac{2}{9}.

We will get 3 \frac{1}{9}.

Hope this helps!

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Find the probability of the following events , when a dice is thrown once:
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Answer:

Step-by-step explanation:

s a die is rolled once, therefore there are six possible outcomes, i.e., 1,2,3,4,5,6.

(a) Let A be an event ''getting a prime number''.

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(d) Let A be the event of getting a number at most 4.

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(ii) Since, a pair of dice is thrown once, so there are 36 possible outcomes. i.e.,

(a) Let A be an event ''a total 6''. Favourable cases for a total of 6 are (2,4), (4,2), (3,3), (5,1), (1,5).

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(b) Let A be an event ''a total of 10n. Favourable cases for total of 10 are (6,4), (4,6), (5,5).

i.e., n(A)=5

P(A)=n(A)n(S)=336=112

(c) Let A be an event ''the same number of the both the dice''. Favourable cases for same number on both dice are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).

i.e., n(A)=6

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(d) Let A be an event ''of getting a total of 9''. Favourable cases for a total of 9 are (3,6), (6,3), (4,5), (5,4).

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