Question

What is the expression and value of "six less than the quotient of a number and two, increased by ten" when n = 8?

Answer 1

Answer:

8

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Answer 2

Option 1 - StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.

Step-by-step explanation:

Given : Expression "six less than the quotient of a number and two, increased by ten".

To find : What is the expression and value of expression when n = 8?

Solution :

Let the number be 'n'.

The quotient of a number and two i.e. $\frac{n}{2}$

Six less than the quotient of a number and two i.e. $\frac{n}{2}-6$

Six less than the quotient of a number and two, increased by ten i.e. $\frac{n}{2}-6+10$

The required expression is $\frac{n}{2}-6+10$.

Now, when n=8,

$\frac{n}{2}-6+10=\frac{8}{2}-6+10$

$\frac{n}{2}-6+10=4-6+10$

$\frac{n}{2}-6+10=8$

The value of the expression is 8.

Therefore, option 1 is correct.

StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.