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topjm [15]
4 years ago
7

35.83 x 0.0028 SHOW WORK! ! ! ! ! ! ! !

Mathematics
2 answers:
Travka [436]4 years ago
5 0

Answer:0.100324


Step-by-step explanation: Something tells me you are not understanding this subject. I already answered one of your questions similar to this one. Maybe pay attention in class.


ArbitrLikvidat [17]4 years ago
5 0

Answer:

1.0*10^(-1)  (but 0.10 would also be appropriate)

Step-by-step explanation:

Rewrite 35.83 x 0.0028 as 3.583*10^1 and 0.0028 as 2.8*10^(-3).

Estimate the product:  36 times 3 is 108.

Multiply 3.583 and 2.8 together, obtaining 10.0324.

Noting that 10^1 * 10^(-3) = 10^(-2), write the intermediate answer as:

10.0234*10^(-2).

Move the decimal point one place to the left, and then, in compensation, rewrite this expression as 1.0234*10^(-1).

Finally, rewrite this result as 1.0*10^(-1).  Since 0.0028 has just 2 signficant figures, 1.0 (2 significant figures) is appropriate.  That's 1.0*10^(-1).

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❗️10 points❗️<br> 1. simplify the radical expression.<br> pleassee
lozanna [386]

Answer:

\frac{\sqrt{10} }{9\\}

Step-by-step explanation:

Square root of 81 is 9

Square root of 10 is fully simplified

3 0
3 years ago
Read 2 more answers
The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for
swat32
Let the price of flowers in September be x, then (100 + 20)/100 * x = $1.50
120/100 * x = $1.50
1.2x = $1.50
x = $1.50/1.2 = $1.25
The price of flowers in September is $1.25

Total money realised in September = $1.25 x 900 = $1,125
40% earned = 0.4 x $1,125 = $450

Total money realised in October = $1.50 x 700 = $1,050
40% earned = 0.4 x $1,050 = $420

The class earned more money in September and they earned $30 more than in October.
7 0
3 years ago
An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (
oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

y^2=1-3x^2

3x^2+y^2=1

\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1

therefore it is a vertical ellipse

thus a=1

b=\frac{1}{\sqrt{3}}

eccentricity of Ellipse

e^2=1-\frac{b^2}{a^2}

e^2=1-\frac{1}{(\sqrt{3})^2}

e^2=1-\frac{1}{3}

e^2=\frac{2}{3}

e=\sqrt{\frac{2}{3}}

Focii are (0,ae) and (0,-ae)

ae=1\times \sqrt{\frac{2}{3}}

thus focii are (0,\sqrt{\frac{2}{3}}) & (0,-\sqrt{\frac{2}{3}})

(b) Length of major axis =2a=2\times 1

length of minor axis=2b=2\times \sqrt{\frac{2}{3}}=2\cdot \sqrt{\frac{2}{3}}

8 0
3 years ago
The interval(s) for which the function shown below is increasing
Oduvanchick [21]

Answer:

everywhere except between 2 and 5

(between -inf and 2 and between 5 and inf)

Step-by-step explanation:

pls brainlist

5 0
3 years ago
Kim and Daniel are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls of
ivanzaharov [21]

There are two equation:

1) From Kim

2) From Daniel


Let:

x be the cost of rolls of plain wrapping paper

y be the cost of rolls of shiny wrapping paper


Kim:

7x + 8y = 140

Daniel:

14x + 7y = 154


<u>Using elimination method:</u>

(7x + 8y = 140) * -2  (Multiplying the equation by -2)

-14x - 16y = -280


-14x  -16y = -280

14x + 7y = 154

------------------------------

0x - 9y = -126

9y = 126 (Negative sign cancels from both sides)

y = 126 /9

y = 14


The cost of each shiny wrapping paper is $14.


Now solve x, you pick any two equation to solve for x.

7x + 8y = 140

7x + 8(14) = 140 (You know from above y =14)

7x + 112 = 140

7x = 28

x = 28/7

x = 4


The cost of each plain wrapping paper is $4.


Solution: (4,14)

4 0
4 years ago
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