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3 years ago

Someone help me I don’t understand the circumference C=2TTr

Mathematics

1 answer:

Irina-Kira [14]3 years ago

4 0

You are being asked to make π the subject in

$C=2πr \:$

So divide both sides of the equation by
$2r$

That is

$\frac{ C}{2r} = \frac{2πr}{2r}$
The you have
$\frac{ C}{2r} = \pi$

or

$\pi = \frac{ C}{2r}$

I hope this is helpful?

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A cell phone plan charges $39.95 a month plus 15 cents per text message sent and 15 cents per text message received. Using s to

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Answer:

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Step-by-step explanation:

I hope this helps :)

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parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm. point F is on RS exactly 5 cm from S. let T be the intersection of PF

Doss [256]

<u>Solution-</u>

Given that,

In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.

Then considering ΔPQT and ΔSTF,

1- ∠FTS ≅ ∠PTQ ( ∵ These two are vertical angles)

2- ∠TFS ≅ ∠TPQ ( ∵ These two are alternate interior angles)

3- ∠TSF ≅ ∠TQP ( ∵ These two are also alternate interior angles)

<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>

∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

$\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS} =\frac{TP}{TF}$

As QS = TQ + TS = 10 (given)

If TS is x, then TQ will be 10-x. Then putting these values in the equation

$\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS}$

$\Rightarrow \frac{8}{5} =\frac{10-x}{x}$

$\Rightarrow x=3.85$

∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm

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