Answer: 4 minutes
Step-by-step explanation: divide 12 and 3
8/12 in its simplest form is 1/3 you can get this by dividing the numerator and denominator by 4 and then by 2
Answer: Choice B

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Explanation:
The given matrix is
![\left[\begin{array}{cc|c}1&5&11\\4&-6&-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%265%2611%5C%5C4%26-6%26-3%5Cend%7Barray%7D%5Cright%5D)
The numbers to the right of the vertical bar represent the values on the right hand side of each equation in the final answer.
The numbers to the left of the bar represent the x and y coefficients of the equations. The first number of any given row is the x coefficient. The second number is the y coefficient.
For instance, the first row has
to indicate the x coefficient is 1, and the y coefficient is 5. We end up with 1x+5y or simply x+5y. Putting everything together, the first equation would be x+5y = 11
Through similar steps, the second equation is 4x-6y = -3
Answer:
2 393/500
Step-by-step explanation:
Answer:
Option C
Step-by-step explanation:
You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.
The total cost has to be in units of $.
There are two types of costs in the problem:
Those that depend on the number of days ($/day
)
Those that depend on the number of students and the number of days ($/(student * day))
If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'
So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:
3 days (Cost of training + Cost of food Miscellaneous expenses :).
Therefore the correct answer is option C:
C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.
The expression that represents the total expense should have a formula similar to this:
![y = (3 days) *([\frac{20.dollars}{(day * student)} + \frac{30.dollars}{(student * day)} + \frac{50.dollars}{(student * day)}] b + \frac{200}{day}) + 1050.dollars](https://tex.z-dn.net/?f=y%20%3D%20%283%20days%29%20%2A%28%5B%5Cfrac%7B20.dollars%7D%7B%28day%20%2A%20student%29%7D%20%2B%20%5Cfrac%7B30.dollars%7D%7B%28student%20%2A%20day%29%7D%20%2B%20%5Cfrac%7B50.dollars%7D%7B%28student%20%2A%20day%29%7D%5D%20b%20%2B%20%5Cfrac%7B200%7D%7Bday%7D%29%20%2B%201050.dollars)
y = 3 ($ 100b + $ 200) + $ 1050