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Radda [10]
3 years ago
5

12.) The table below shows pork production in China from 2000 to 2007. Use a calculator to find the line of best fit. b. Use you

r linear model to predict how many metric tons of pork will be produced in 2025.. c. Use your linear model to predict when production is likely to reach 100,000 metric tons.. [Year: 2000, 2001, 2002, 2003, 2004, 2005, 2006, 2007. Production(metric tons): 40,475, 42,010, 43,413, 45,331, 47,177, 50,254, 52,407, 54,491.].
Mathematics
1 answer:
Brrunno [24]3 years ago
8 0
Using the linearization in this data through the  calculator program, we plug in the production in y and the year in x column. The equation is equal to y = 2053x + 39759. Hence after 25 years at 2025, production is  y = (2053)(25) + 39759 = 91084. To reach 100,000 metric tons, 100000 = 2053x + 39759, we need x years equal to 29.3 years, hence on year 2029.
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At 8:00 a.m., there were t inches of snow on the ground. At 5:00 p.m., there were 3t inches of snow on the ground. How many more
Anastaziya [24]

we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>

We know that at 8:00 a.m. there were t inches of snow in the ground.

At 5:00 p.m. there were 3t inches of snow in the ground.

Then the difference between the heights of the snow is:

3t- t = 2t

And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:

3t = 12in

t = (12in)/3 = 4 in

Replacing that in the difference of heights:

2t = 2*4in = 8in

From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

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3 0
2 years ago
Can someone help me with this thanks ​
Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}

\frac{BC}{sinA}=\frac{AB}{sinC}

\frac{2}{sin25}=\frac{3}{sinC}

\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

\frac{BC}{sinA}=\frac{AC}{SinB}

\frac{2}{sin25}=\frac{l}{sin(115.66)}

l=\frac{2\times sin(115.66)}{sin25}

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

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8 0
2 years ago
Graph this down below​
Helen [10]

Answer:

the graph would start at (0,2) [2 points up from the origin] and then go over 3 up 2, and repeat that over 3 up 2 until you've completed your line to the extent needed

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Answer:

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Step-by-step explanation:

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Answer:

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all angles in an equilateral triangle equal 60 because 180 ÷ 3 = 60

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