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german
3 years ago
10

Find the largest interval which includes x = 0 for which the given initial-value problem has a unique solution. (Enter your answ

er using interval notation.) (x − 4)y'' + 5y = x, y(0) = 0, y'(0) = 1
Mathematics
1 answer:
blagie [28]3 years ago
5 0
The answer is 46^  y equals o
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Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5
hjlf
The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5
5 0
3 years ago
Amy bought a bag of chips for 0.75, a sandwhich for 5.50, a bottle of water for 1.60. How much does amy have left from 10.
ch4aika [34]

Answer:

Amy would have 2.15 left

Step-by-step explanation:

To find out how much she has left, subtract the cost of the items from 10.

10 - 0.75 - 5.50 - 1.60 = 2.15

8 0
2 years ago
ILL GIVE BRAINLIEST!! PLS HELP!!! Ten students are taking both algebra and drafting. There are 24 students taking algebra. There
Minchanka [31]

Answer:

15 students

Step-by-step explanation:

from the algebra = 24 - 10 = 14

from the draft = 11 - 10 = 1

14 + 1 = 15

the total students that are taking algebra or drafting but not both is 15 students

4 0
3 years ago
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Which statement compares the two numbers correctly?
Alex_Xolod [135]
Six hundred seventy-two thousandths <0.8
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2 years ago
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A line joins the point
Harrizon [31]

Intersection of the first two lines:

\begin{cases}5x - 2y + 3 = 0\\4x - 3y + 1 = 0\end{cases}

Multiply the first equation by 4 and the second by 5:

\begin{cases}20x - 8y + 12 = 0\\20x - 15y + 5 = 0\end{cases}

Subtract the two equations:

(20x - 8y + 12)-(20x - 15y + 5)=0 \iff 7y+7=0 \iff y=-1

Plug this value for y in one of the equation, for example the first:

5x - 2\cdot (-1) + 3 = 0\iff 5x+5=0 \iff x=-1

So, the first point of intersection is (-1,-1)

We can find the intersection of the other two lines in the same way: we start with

\begin{cases}x=y\\x=3y+4\end{cases}

Use the fact that x and y are the same to rewrite the second equation as

x=3x+4 \iff 2x=-4 \iff x=-2

And since x and y are the same, the second point is (-2, -2)

So, we're looking for a line passing through (-1,-1) and (-2, -2). We may use the formula to find the equation of a line knowing two of its points, but in this case it is very clear that both points have the same coordinates, so the line must be y=x

In the attached figure, line 5x - 2y + 3 = 0 is light green, line 4x - 3y + 1 = 0 is dark green, and their intersection is point A.

Simiarly, line x=y is red, line x = 3y + 4 is orange, and their intersection is B.

As you can see, the line connecting A and B is the red line itself.

5 0
3 years ago
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