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3 years ago

Answer this ASAP I really need it

Mathematics

1 answer:

Ede4ka [16]3 years ago

8 0

Given the expression
-2 + 6.45z - 6 + (-3.25z)

First, classify like terms, constant with constant, coefficient-variable with coefficient-variable
-2 + 6.45z - 6 + (-3.25z)
= 6.45z + (-3.25z) - 2 - 6

Second, combining like terms
= 6.45z + (-3.25z) - 2 - 6
= 6.45z - 3.25z - 8
= 3.20z - 8

The simplest form is 3.20 - 8

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Evaluate 8-m/n +m when m=8 and n=2

RUDIKE [14]

Substitute the answer: therefore, 8-8/2+8= 0/10 in fraction form, but as you feather simplify 0 divide by 10 you'll get the answer as 0.

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3 years ago

What is the distance of a car traveling with a velocity of 20 m/s north in 5 seconds

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2 years ago

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2 years ago

Read 2 more answers

FIND THE AREA...!!!!!

k0ka [10]

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3 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

2 years ago