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erastova [34]
2 years ago
9

Amina has 6 ¾ L of juice that she wants to pour into ¾ L containers. What is the number of containers that she can fill?

Mathematics
1 answer:
dolphi86 [110]2 years ago
4 0

Answer:

She can fill 9 containers

Step-by-step explanation:

you do 6 3/4 dived by 3/4 and you get 9

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The height of a stack of 12 pennies is 18.24 millimeters. What is the thickness of each penny.
Helga [31]
I’m not great at math so I could easily be wrong, but

I divided the 18.24 millimeters by 12 pennies and got 1.52

So if the pennies are all the same size, each penny should 1.52 millimeters.

To show work:

18.24/12=1.52
4 0
3 years ago
Write an equation for a line perpendicular to y=3x−1 and passing through the point (-9,4)
Vedmedyk [2.9K]

Answer:

y=-1/3x+1

Step-by-step explanation:

(picture explains)

6 0
3 years ago
Find the value of x.<br> (16x-4)°<br> 58°<br> (9x-6)°
mars1129 [50]
16x - 4 + 58 + 9x - 6 = 180
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5 0
2 years ago
Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose P(V) = 0.17
ArbitrLikvidat [17]

Answer: 0.82

Step-by-step explanation:

The probability of the computer not containing neither a virus nor a worm is expressed as P(V^{C}∩W^{C}) , where P(V^{C}) is the probability that the event V doesn't happen and P(W^{C}) is the probability that the event W doesn't happen.

P(V^{C})= 1-P(V) = 1-0.17 = 0.83

P(W^{C})=1-P(W) = 1-0.05 = 0.95

Since V^{C} and W^{C} aren't mutually exclusive events, then:

P(V^{C}∪W^{C}) = P(V^{C}) + P(W^{C}) - P(V^{C}∩W^{C})

Isolating the probability that interests us:

P(V^{C}∩W^{C})= P(V^{C}) + P(W^{C}) - P(V^{C}∪W^{C})

Where P(V^{C}∪W^{C}) = 1 - 0.04 = 0.96

Finally:

P(V^{C}∩W^{C}) = 0.83 + 0.95 - 0.96 = 0.82

5 0
3 years ago
Find the distance between the points (3 4) and (4 3)​
Usimov [2.4K]

Answer:

\sqrt{2} or 1.414213

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

d = \sqrt{(x_{2} -x_{1})^{2} + (y_{2} - x_{1})^{2}  }

d = distance

(x_{1}, y_{1}) = coordinates of the first point

(x_{2}, y_{2}) = coordinates of the second point

8 0
3 years ago
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