Assume that all triangles have interior angles less than 90°.A surveyor sights on a survey marker that is 132.3m distant. She ne
eded to turn her transit (her survey instrument) 75° to sight on a second survey marker. She knows that from the second marker, the angle between the line of site from her own position and the first marker is 68°. How far is she from the second marker?
1 answer:
Answer:
85.9 m
Step-by-step explanation:
The law of sines can help figure this.
The remaining angle in the triangle is ...
180° -75° -68° = 37°
This is the angle opposite the leg from the surveyor to the second marker. Referencing the attachment, we have ...
b/sin(B) = c/sin(C)
b = sin(B)·c/sin(C) = 132.3·sin(37°)/sin(68°) ≈ 85.873 . . . meters
The surveyor is about 85.9 meters from the second marker.
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Answer:
Yes,planner has met the minimum height, as minimum height was 9 feet and maximum height of arc is 9.6 feet
Step-by-step explanation:
The question is incomplete as all the details have not been given in the question.I have attached the complete question and its options at the bottom. Consult in for better understanding.
As we can see that at the mid value, for x=4, the value of f(x)=9.4
It means that the maximum height occurs at mid of the arc where it is height is 9.6 feet above the ground.
It means that the planner has met the minimum height, as minimum height was 9 feet and maximum height of arc is 9.6 feet
