Answer:
y=x+70
Step-by-step explanation:
Slope of 1, and has a y-intercept of 70. So slope-intercept form would be y=m(x) +b where M is the slope and B is the intercept.
They are called unike fractions. If u would want to do anything to them u would have to make the denominaters the same
Answer:
Step-by-step explanation:
When answering questions like this, we have to first decide which function we have to use. This is done by looking at the given domains (the x≤-2 etc). The first question ( f(-2) ), means we have to choose the function that applies to the x-coordinate -2. x=-2 is part of the section x ≤-2 since the sign means larger or equal to -2. Hence, we use the function 2x+8 to calculate f(-2). After finding this, the solving is relatively easy, just fill in the x-coordinate:
f(-2) = 2 * -2 + 8 = -4 + 8 = 4
The second one needs the same method. x=3 belongs in the section
-2 < x ≤ 3, since the final part means x is smaller or equal to 3, and in this case it is. Hence we use
here:
f(3) = 3² - 3 = 9 - 3 = 6
I hope this helps! Feel free to reach out if you still have questions
The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.
According to the given question.
The total number of elements, n = 3
The number of elements to be selected at a time when repetition is allowed, r = 5
Since, we know that " the number of ways or permutations of n things taken r all at a time, when repetition of things are allowed, is
.
Therefore,
The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed
= 
= 243
Hence, the number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.
Find out more information about permuations here:
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Answer: The answer is 
Step-by-step explanation: Given that the area of the whole circle is represented by the expression

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.
Now, if 'r' represents the radius of the circle, then we have

Thus, the area of the outer ring is
