Answer:
I just need points I have ro freaking clue
Answer:
c
Step-by-step explanation:
just did it on the assignment
Answer:
Step-by-step explanation:
in third quadrant sin is negative.
sin² θ+cos² θ=1
sin²θ+(-16/20)²=1
sin²θ+(-4/5)²=1
sinθ=±√(1-16/25)
=±√((25-16)/25)
=±√(9/25)
=±3/5
so
sin θ=-3/5
<h3>
Answer: 50</h3>
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Explanation:
We simply multiply the two values given to us
600*(1/12) = 600/12 = 50
We expect about 50 bulbs to be defective.
Note how if we had 50 bad bulbs, then 50/600 = (1*50)/(12*50) = 1/12 of the batch of 600 bulbs is defective.
Answer:
So possibilities of zeroes are:
Positive Negative Imaginary
1 1 2
3 1 0
Zeroes = -1.4549, 1.2658, 0.34457-1.0503i, 0.34457+1.0503i.
Step-by-step explanation:
Note: Descartes' Rule of Signs is used to find the signs of zeroes not the exact value.
The given function is
Degree of polynomial is 4 so number of zeroes is 4.
There are three sign changes, so there are either 3 positive zeros or 1 positive zero.
Now, put x=-x in f(x).
There is one variation in sign change, so there is 1 negative zero.
So possibilities of zeroes are:
Positive Negative Imaginary
1 1 2
3 1 0
Using graphing calculator the zeroes of given function are -1.4549, 1.2658, 0.34457-1.0503i and 0.34457+1.0503i.