How to find the area of a regular polygon

1 answer:

Taya2010 [7]3 years ago

6 0

You can always find the area from breaking it up into smaller shapes. For example, a hexagon is basically 2 trapezoids.
Some formulas for different shapes.
Trapezoid: <span>height × (base1 + base2) / 2
Rectangle: length x width
Parallelogram: height x base
Triangle height x base / 2</span>

You might be interested in

Find the total surface area of this cylinder.

Natali5045456 [20]

Answer

967.1 squared cm, multiply area of base by two, and perimeter by 15.

7 0

3 years ago

Which is the difference of 21 1/4 - 18 2/4? A:2 1/4. B:2 2/4. C:2 3/4. D:3 1/4.

seropon [69]

Answer:

2 3/4 C

Step-by-step explanation:

$(21+\frac{1}{4})-(18+\frac{2}{4})\\=21-18+\frac{1}{4} -\frac{2}{4} \\=3-\frac{1}{4} \\=\frac{12-1}{4} \\=\frac{11}{4} \\=2\frac{3}{4} \\or\\21\frac{1}{4} -18\frac{2}{4} \\=\frac{85}{4} -\frac{74}{4} \\=\frac{85-74}{4} \\=\frac{11}{4} \\=2\frac{3}{4}$

3 0

4 years ago

Help... ANYONE PLZZZ

mote1985 [20]

First triangle:
2x+2x+x=180
x=36

second triangle:
7x+3x+90=180
x=9

third triangle:
2x+x+x=180
x=45

good luck!!

4 0

3 years ago

Read 2 more answers

HELP ME PLEASEEEEEEEEEE It takes $\frac{1}{2}$ hours to drive from A-ville to B-town. It takes three-fifths of the time it takes

statuscvo [17]

Answer:

Step-by-step explanation:

It takes 1/2 hours to drive from A-ville to B-town. It takes three-fifths of the time it takes to drive from A-ville to B-town to drive from B-town to C City.

To drive from B-town to C City, it will take:

1/2 * 3/5

= 3/10 hours

5 0

4 years ago

Read 2 more answers

Explain why the graph of a linear equation in the form of y=c is a horizontal line

xeze [42]

Let's say "c" is a constant, hmmmm any constant, for any value whatsoever of "x", "y" is always that constant, for example, say c = 3, thus y = 3, so a table for it will look like

$\bf \begin{array}{ccll}
x&y\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-\infty&3\\
-6&3\\
-5&3\\
-4&3\\
-3&3\\
-2&3\\
-1&3\\
0&3\\
1&3\\
2&3\\
3&3\\
4&3\\
5&3\\
6&3\\
+\infty&3
\end{array}$

now, if you plot those points, it'd looks like the picture below.

4 0

3 years ago