Ask question

Ask question

All categories

3 years ago

11

How does factoring help solve quadratic equations?

1 answer:

n200080 [17]3 years ago

5 0

Answer:

o solve an quadratic equation using factoring : 1 . Transform the equation using standard form in which one side is zero. ... Set each factor to zero (Remember: a product of factors is zero if and only if one or more of the factors is zero).

Step-by-step explanation:

You might be interested in

The price of a CD that sells for 21% more than the amount (m) needed to manufacture the CD

zhuklara [117]

Are you looking for an equation or is there more to the question

5 0

3 years ago

Find the equation of the straight line which passes through each of the following pairs of points.

Tems11 [23]

Answer:

y = 3x + 1

Step-by-step explanation:

First, find slope:

$y2 - y1 / x2 - x1$

$10 - 4/ 3 - 1 = 6 / 2 = 3$

Then, put the equation into point-slope form using the point (1, 4):

$y - y1 = m(x - x1)$

where m is the slope

y - 4 = 3(x - 1)

If you want to put this into slope-intercept form, it would be

$y-4=3(x-1)\\y - 4 = 3x - 3\\y = 3x + 1$

4 0

3 years ago

Use Julia’s work and finish finding the areas of the faces what is the surface area of the rectangular pyramid

hoa [83]

Answer:

The surface area of the rectangular pyramid is $SA=109.50\ m^{2}$

Step-by-step explanation:

we know that

The surface area of the rectangular prism is equal to the area of the rectangular base plus the area of the four triangular faces

so

$SA=(8)(5)+2[14.75]+2[\frac{1}{2}(8)(5)]$

$SA=40+29.50+40$

$SA=109.50\ m^{2}$

6 0

3 years ago

☆pls help no one has helped me and I'm so confused!

motikmotik

Answer:

Step-by-step explanation:

a). $\frac{5\pm\sqrt{-4}}{3}$ = $\frac{5}{3}\pm \frac{\sqrt{-4}}{3}$

= $\frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}$

= $\frac{5}{3}\pm\frac{2i}{3}$ [Since, i = $\sqrt{(-1)}$ ]

b). $\frac{10\pm\sqrt{-16}}{2}$ = $\frac{10}{2}\pm \frac{\sqrt{-16}}{2}$

= $5\pm \frac{4\sqrt{-1}}{2}$

= 5 ± 2i [Since, i = $\sqrt{(-1)}$ ]

c). $\frac{-3\pm \sqrt{-144}}{6}$ = $-\frac{3}{6}\pm \frac{\sqrt{-144}}{6}$

= $-\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}$

= $-\frac{1}{2}\pm 2\sqrt{-1}$

= $-\frac{1}{2}\pm 2i$ [Since, i = $\sqrt{(-1)}$ ]

4 0

2 years ago

I need help please help me ;-;

vodomira [7]

Answer:

I think option A is correct answer

3 0

2 years ago

Read 2 more answers