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3 years ago

Help I’m rly stuck plzzzzzzz help I’m dying to get through this question I’ll do anything !!!!

Mathematics

2 answers:

Mashutka [201]3 years ago

8 0

Answer:

you answer is 2 because 2 - 6 is -4

ArbitrLikvidat [17]3 years ago

5 0

Answer:

d = 2

Step-by-step explanation:

d - 6= -4

d - 6 + 6 = -4 + 6 (were trying to get rid of the -6 from the left side and bring it to the right side so what you do to one side (which is +6 to cancel out with -6) you do to the other side as well you be fair)

d = -4 + 6

d = 2

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Help me on this question please

Luba_88 [7]

Sorry hun I’ve never learned that

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2 years ago

While traveling to Europe phlegm exancheged 250 US dollars he spent 150 euros on his trip after returning to the United States h

anzhelika [568]

1euro = 1.3687 USD

So 150 Euros = 150*1.3687 USD

=<span>205.305 USD

So he spent $205.305 USD on his trip.

He started off with $250 so to find the amount left we just take

250 - 205.305

= $44.695

Or 44 dollars and 69.5 cents. It's a weirdly exact amount, sure, but the question had a very precise exchange rate, so we'll assume this is fine. </span>

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3 years ago

Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

6 0

3 years ago

The cost of a lack has increased by 30% to £65. Work out the original price

Sveta_85 [38]

Cost of lack increased by 30%

new cost of lack will be = 100% + 30% = 130%

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Thus 130% of original cost = 65

100% of original cost = 65 × 100/130 = £50

Thus original price was £50

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3 years ago

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Mars2501 [29]

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3 years ago