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Ann [662]
3 years ago
14

What is the minimum number of bits required to store 11 different values?

Computers and Technology
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

4 bits are required. 4 bits can represent 16 different values (2*2*2*2 or ). 3 bits can only represent 8 different values. In the general case n bits can represent values, or correspondingly m values can be represented by bits.

You might be interested in
graphic designers can compress files in different formats . One of the formats ensures that the quality and details of the image
musickatia [10]

Answer:

The format that is used is: PNG

Explanation:

7 0
3 years ago
Create a class, using separate files, named DynamicGrades. (2 points) This class has three data members: an int that represents
Alex

Answer:

See explaination

Explanation:

#include <iostream>

using namespace std;

//DynamicGrades.h

class DynamicGrades

{

public:

DynamicGrades(int size);

~DynamicGrades();

void mutate(int studentId, int index, int grade);

int getGrade(int studentId, int index);

private:

int m_studentId;

int m_noofGrades;

int* m_dynamicArr;

};

//DynamicGrades.cpp

#include "DynamicGrades.h"

DynamicGrades::DynamicGrades(int size)

{

m_noofGrades = size;

m_dynamicArr = new int[m_noofGrades] {0};

}

DynamicGrades::~DynamicGrades()

{

if(nullptr != m_dynamicArr)

delete[] m_dynamicArr;

}

void DynamicGrades::mutate(int studentId, int index, int grade)

{

m_studentId = studentId;

if (index < m_noofGrades)

m_dynamicArr[index] = grade;

}

int DynamicGrades::getGrade(int studentId, int index)

{

if (index >= m_noofGrades)

return -1;

return m_dynamicArr[index];

}

//Main.cpp

#include "DynamicGrades.h"

int main()

{

DynamicGrades* grade = new DynamicGrades(5);

DynamicGrades grade2(10);

for (int i = 0;i < 5;++i)

{

grade->mutate(2, i, i + 1);

}

for (int i = 0; i < 10; i++)

{

grade2.mutate(3, i, i + 1);

}

cout << "Grades are " << endl;

for (int i = 0;i < 5;++i)

{

cout << grade->getGrade(2, i) <<" ";

}

cout << endl;

for (int i = 0; i < 10; i++)

{

cout << grade2.getGrade(3, i) << " ";

}

}

3 0
3 years ago
Write an SQL statement to display for every restaurant the name of the restaurant (where the name of the restaurant consists of
Rainbow [258]

Using the knowledge in computational language in SQL it is possible to write the code that display for every restaurant the name of the restaurant  and for every category of menu item its description.

<h3>Writting the code:</h3>

<em>INSERT INTO Dish </em><em>Values</em><em>(13, 'Spring Rolls', 'ap');</em>

<em>INSERT INTO Dish Values(15, 'Pad Thai', 'en'); </em>

<em>INSERT INTO Dish Values(16, 'Pot Stickers', 'ap');    </em>

<em>INSERT INTO Dish Values(22, 'Masaman Curry', 'en');   </em>

<em>INSERT INTO Dish Values(10, 'Custard', 'ds');   </em>

<em>INSERT INTO Dish Values(12, 'Garlic Bread', 'ap');    </em>

<em>INSERT INTO Dish Values(44, 'Salad', 'ap');    </em>

<em>INSERT INTO Dish Values(07, 'Cheese Pizza', 'en');   </em>

<em>INSERT INTO Dish Values(19, 'Pepperoni Pizza', 'en');    </em>

<em>INSERT INTO Dish Values(77, 'Veggie Supreme Pizza', 'en');</em>

<em />

<em>INSERT </em><em>INTO MenuItem Values(0, 0, 13, 8.00);</em>

<em>INSERT INTO </em><em>MenuItem </em><em>Values(1, 0, 16, 9.00);</em>

<em>INSERT INTO MenuItem Values(2, 0, 44, 10.00);</em>

<em>INSERT INTO MenuItem Values(3, 0, 15, 19.00);</em>

<em>INSERT INTO MenuItem Values(4, 0, 22, 19.00);</em>

<em>INSERT INTO MenuItem Values(5, 3, 44, 6.25);</em>

<em>INSERT INTO MenuItem Values(6, 3, 12, 5.50);</em>

<em>INSERT INTO MenuItem Values(7, 3, 07, 12.50);</em>

<em>INSERT INTO MenuItem Values(8, 3, 19, 13.50);</em>

<em>INSERT INTO MenuItem Values(9, 5, 13, 6.00);</em>

<em>INSERT INTO MenuItem Values(10, 5, 15, 15.00);</em>

<em>INSERT INTO MenuItem Values(11, 5, 22, 14.00);</em>

See more about SQL atbrainly.com/question/13068613

#SPJ1

4 0
1 year ago
True or False?
Nadya [2.5K]

False.

The different between break and continue instruction is that with break you exit the loop, and with continue you skip to the next iteration.

So, for example, a loop like

for(i = 1; i <= 10; i++){

   if(i <= 5){

       print(i);

   } else {

       break;

   }

}

will print 1,2,3,4,5, because when i=6 you will enter the else branch and you will exit the loop because of the break instruction.

On the other hand, a loop like

for(i = 1; i <= 10; i++){

   if(i % 2 == 0){

       print(i);

   } else {

       continue;

   }

}

Will print 2,4,6,8,10, because if i is even you print it, and if i is odd you will simply skip to the next iteration.

6 0
3 years ago
Please help me. i will mark you brailiest
Stolb23 [73]

Answer:

Simple, really

Explanation:

3Rd one is pretty easy, all you have to do is read closely.

3 0
3 years ago
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