The question is a bit ambiguous: you may mean
![\sqrt{3x+8}](https://tex.z-dn.net/?f=%5Csqrt%7B3x%2B8%7D)
or
![\sqrt{3x}+8](https://tex.z-dn.net/?f=%5Csqrt%7B3x%7D%2B8)
Anyway, in both cases, the domain of a function involving a square root is found by imposing the content of the root to be greateer than or equal to zero. So, in the first case you have
![3x+8\geq 0 \iff 3x\geq -8 \iff x\geq -\dfrac{8}{3}](https://tex.z-dn.net/?f=3x%2B8%5Cgeq%200%20%5Ciff%203x%5Cgeq%20-8%20%5Ciff%20x%5Cgeq%20-%5Cdfrac%7B8%7D%7B3%7D)
In the second case, you have
![3x\geq 0 \iff x\geq 0](https://tex.z-dn.net/?f=3x%5Cgeq%200%20%5Ciff%20x%5Cgeq%200)
Answer:
Step-by-step explanation:
x - 3y = 4
x - 3(-3) = 4
x + 9 = 4
x = -5
(-5, -3)
-11 - 3y = 4
- 3y = 15
y = -5
(-11, -5)
I don't see how (0, -3) could be a solution to the equation.
Let number of shirt bought be x
13(X/4)+20(X/3)=833
3.25X+(20/3)X=833
X=833/(20/3+3.25)
X=84
I’m sorry, I wish I knew this one and I would help