We are given the following variables:
μ = the sample mean = 152 pounds
σ = the standard deviation = 26 pounds
x = the sample value we want to test = 180 pounds
n = the sample size = unknown
MOE = margin of error = 4% = 0.04
Confidence level = 96%
The first thing we can do is to find for the value of z
using the formula:
z = (x – μ) / σ
z = (180 – 152) / 26
z = 1.0769 = 1.08
Since we are looking for the people who weigh more than
180 pounds, therefore this is a right tailed z test. The p value is:
p = 0.1401
Then we can use the formula below to solve for n:
n = z^2 * p * (1 – p) / (MOE)^2
n = 1.08^2 * 0.1401 * (1 – 0.1401) / (0.04)^2
n = 87.82 = 88
Therefore around 88 people must be surveyed.
Answer:
-a^2 or -b^2.
Step-by-step explanation:
Answer:
8.025
Step-by-step explanation:
If you count the zeros in 1000, it's three. Count three starting from the back of 25. Add 0 in front of 25 to make it a three digit number. You then put the decimal point with the whole number.
for 3/8 you can times by 12 to make 36/96
for 5/12 you can times by 8 to make 40/96
now that they have the same denominators (bottoms), you can add them to make
36/96 + 40/96 =76/96
simplified
= 38/48
=19/24
First convert all to decimal.
7/9 = 0.777
8/11 = 0.727
0.79 = 0.79
84% = 0.84
4/5 = 0.8
Now line them back up in order from least to greatest based on the decimal value.
Final answer:
8/11, 7/9, 0.79, 4/5, 84%
