Answer:
As x ⇒-∞, P(x) ⇒ -∞
As x ⇒ ∞, P(x) ⇒ ∞
Step-by-step explanation:
To find left hand end behavior, plug in negative infinity into the function and evaluate...
P(x) = 3(-∞) = -3(∞) = -∞
The 'y' values of the function decrease towards negative infinity as the 'x' values approach negative infinity
P(x) = 3(∞) = ∞
The 'y' values of the function increase towards positive infinity as the 'x' values approach positive infinity
Answer: 8 3/4
Step-by-step explanation:
3x(4x-5+3); where x is 1/2
Substitute the value 1/2 with x
3 1/2 (4 1/2 - 5+3)
7/2 (9/2 -2)
7/2 (5/2)
35/4 = 8 3/4
Given P is T, q is F and r is F.
Let us find p ↔ q first.
↔ is called bi-conditional operator and is true when p and q both are matched.
Since here p is T and q is F, p↔q is F. ( Since p and q are not matching)
~p v r = ~T v F = F v F = F
Hence (p↔q)→(~pvr) = F → F = T (Since conditional operator → is false if and if first proposition is T and second proposition is F, for all other values it is T)
Three times the result of a number plus a number equals two times a number minus a number.
or
Three times the result of a variable plus a variable equals two times a variable minus a variable.
