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RideAnS [48]
3 years ago
13

PLEASE HELP WILL GIVE BRAINLIEST Which of the following scale factors will result in an enlargement? A. k < –1 B. –1 < k &

lt; 0 C. 0 < k < 1 D. k = 1
Mathematics
1 answer:
Sergio [31]3 years ago
5 0

Answer: OPTION A.

Step-by-step explanation:

By definition, a dilation can be an enlargement or a reduction of the shape.

An enlargement is when dilation creates a larger image and a reduction is when dilation creates a smaller image.

When, the scale factor is greater than 1, the image is an enlargement and when the scale factor is between 0 and 1, the image is a reduction.

It is important to know that with a negative scale factor the enlargement will will be inverted and it will also be on the other side of the center of dilation.

Knowing this, we can say that the scale factor that will result in an enlargement is:

k

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Answer quickly thank you so much!!!!!!!!!!!!!!!!!!!!!
marin [14]
The answer is C I think
3 0
3 years ago
How much does he/she pay with 10 %
ss7ja [257]

Answer:

5085

Step-by-step explanation:

price after discount is 5000- 10% of 5000 = 4500

V.A.T = 13% of 4500 = (13/100)*4500= 13*45= 585

Price after V.A.T = 4500 + 585 = 5085

5 0
3 years ago
Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a
rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that \sigma = 2

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when M = 0.5. So

M = z\frac{\sigma}{\sqrt{n}}

0.5 = 1.96\frac{2}{\sqrt{n}}

0.5\sqrt{n} = 2*1.96

Dividing both sides by 0.5

\sqrt{n} = 4*1.96

(\sqrt{n})^2 = (4*1.96)^2

n = 61.5

Rounding up

We would have to take a sample of 62 to achieve this result.

8 0
3 years ago
A production manager at a wall clock company wants to test their new wall clocks. The designer claims they have a mean life of 1
Harman [31]

The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.

Given mean of 14 years, variance of 25 and sample size is 50.

We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.

μ=14,

σ=\sqrt{25}=5

n=50

s orσ =5/\sqrt{50}=0.7071.

This is 1 subtracted by the  p value of z when X=12.5.

So,

z=X-μ/σ

=12.5-14/0.7071

=-2.12

P value=0.0170

1-0.0170=0.9830

=98.30%

Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.

Learn more about probability at brainly.com/question/24756209

#SPJ4

There is a mistake in question and correct question is as under:

What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?

5 0
2 years ago
What is the answer text
r-ruslan [8.4K]
3/4 of milk: because the bigger the number the smaller the size
5 0
3 years ago
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