Answer: A light bulb in the same room at the same temperature.
Explanation: Yw, BYE!!!
Answer:
Only one seven carbon hydrocarbon was produced.
Explanation:
- Alkynes are reduced completely in presence of
to produce alkanes. - Hydrogenation in presence of Pt is a simple nucleophilic addition process where
molecule adds onto an unsaturated bond. - Hept-1-yne, hept-2-yne and hept-3-yne are constitutionally isomeric to each other. Hence, after complete reduction, all three alkynes produced heptane as only product.
- So, only one seven carbon hydrocarbon was produced.
By calculating it's number of GROUP........
Answer:
See explanation
Explanation:
The question is incomplete because the image of the alcohol is missing. However, I will try give you a general picture of the reaction known as hydroboration of alkenes.
This reaction occurs in two steps. In the first step, -BH2 and H add to the same face of the double bond (syn addition).
In the second step, alkaline hydrogen peroxide is added and the alcohol is formed.
Note that the BH2 and H adds to the two atoms of the double bond. The final product of the reaction appears as if water was added to the original alkene following an anti-Markovnikov mechanism.
Steric hindrance is known to play a major role in this reaction as good yield of the anti-Markovnikov like product is obtained with alkenes having one of the carbon atoms of the double bond significantly hindered.
The answer is Independent Variable
