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Nikitich [7]
3 years ago
10

Ano-ano ang mensahe ng grupo ng el gamma penumbra sa kanilang palabas​

Chemistry
1 answer:
Alexxandr [17]3 years ago
6 0

Answer:

Pag-alaga ng kalikasan, pagpapakita ng mga tanawin o kagandahan ng Pilipinas

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How do water particles move in a wave? A. They move forward with the wave. B. They move in a circular motion. C. They move up an
Olin [163]
Sorry if I'm wrong but I think that it is B. 
4 0
2 years ago
An object that is already moving can . . .
Yuri [45]
An object that is not already moving will begin to move in the direction of the larger force. An object that is already moving will change its speed and/or its direction.
4 0
3 years ago
What are the the basic cloud types?
shutvik [7]

Answer:

they are 10 but I'll be listing three

Explanation:

cirrus,cirrocumulus and cirrostratus

I hope this helps....good luck with the rest...again, I hope this helps

8 0
3 years ago
n an experiment, 39.26 mL of 0.1062 M NaOH solution was required to titrate 37.54 mL of \ v unknown acetic acid solution to a ph
olasank [31]

Answer:

Molarity: 0.111M

% (w/w): 0.666

Explanation:

The reaction of NaOH with acetic acid (CH₃COOH) is:

NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O

<em>where 1 mole of NaOH reacts per mole of acetic acid producing 1 mole of water and 1 mole of sodium acetate.</em>

As 39.26mL ≡ 0.03926L of 0.1062M are required to titrate the solution of acetic acid. Moles are:

0.03926L × (0.1062mol / L) = 4.169x10⁻³ moles of NaOH. As 1 mole of NaOH reacts per mole of acetic acid:

4.169x10⁻³ moles of CH₃COOH.

Molarity is defined as ratio between moles of substance and volume of solution in liters. Thus, molarity of acetic acid solution is:

4.169x10⁻³ moles of CH₃COOH / 0.03754L = <em>0.111M</em>

<em></em>

As molar mass of acetic acid is 60g/mol, 4.169x10⁻³ moles weights:

4.169x10⁻³ moles × (60g / mol) = <em>0.2501 g of acetic acid</em>

Now, assuming density of solution as 1.00g/mL, 37.54mL weights <em>37.54g</em>.

Thus, percent by weight is:

0.2501g CH₃COOH / 37.54g × 100 = <em>0.666% (w/w)</em>

8 0
2 years ago
at a particulat temperature, a smaple of pure water has a Kw of 7.7x10-14. what is the hydroxide concentration of this sample
ycow [4]

Answer: The hydroxide concentration of this sample is 3.85\times 10^{-7}

Explanation:

When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.

The ionic product for water is written as:

K_w=[H^+]\times [OH^-]

7.7\times 10^{-14}=[H^+]\times [OH^-]

As [H^+]=[OH^-]

2[OH^-]=7.7\times 10^{-14}

[OH^-]=3.85\times 10^{-7}

Thus hydroxide concentration of this sample is 3.85\times 10^{-7}

4 0
2 years ago
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