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Dahasolnce [82]
2 years ago
5

A 1.00 L of a solution is prepared by dissolving 125.6 g of NaF in it. What would be the molarity of this solution?

Chemistry
1 answer:
DedPeter [7]2 years ago
4 0

Answer:

2.99 M

Explanation:

In order to solve this problem we need to keep in mind the definition of molarity:

  • Molarity = moles of solute / liters of solution

In order to calculate the moles of solute, we <u>convert 125.6 g of NaF into moles</u> using its <em>molar mass</em>:

  • 125.6 g NaF ÷ 42 g/mol = 2.99 mol NaF

As the volume is already given, we can proceed to <em>calculate the molarity</em>:

  • Molarity = 2.99 mol / 1.00 L = 2.99 M
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