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Aliun [14]
3 years ago
10

Please help me I really need help. I will mark you brainliest​

Mathematics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

15? I might be wrong tho.....

Step-by-step explanation:

I looked at the other shape and figured out the difference between 14 and 22 was 8, so I added 8 to 7 and got 15.

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Prove that (n+5)^2-(n+3)^2 is a multiple of 4 for all positive integer values of n
hodyreva [135]

Answer:

Proved

Step-by-step explanation:

Given

(n+5)^2-(n+3)^2

Required

Show that (n+5)^2-(n+3)^2 is a multiple of 4

Expand each bracket

(n+5)(n+5)-(n+3)(n+3)

Open brackets

n^2 + 5x + 5x + 25 - (n^2 + 3x + 3x + 9)

n^2 + 10x + 25 - (n^2 + 6x + 9)

Open bracket

n^2 + 10x + 25 - n^2 - 6x - 9

Collect Like Terms

- n^2 + n^2 - 6n + 10n + 25  - 9

- 6n + 10n + 25  - 9

4n + 25  - 9

4n + 16

Factorize

4(n + 4)

Hence, the multiples of (n+5)^2-(n+3)^2 are 4 and (n + 4)

8 0
4 years ago
Tell whether the valuation is a solution of the inequality r + 4 > 8 ; r = 2
aleksandr82 [10.1K]

Answer:

Not a solution.

Step-by-step explanation:

Step 1: Write inequality

r + 4 > 8

Step 2: Solve for <em>r</em>

  1. Subtract 4 on both sides: r > 4

Step 3: Determine

r = 2

2 > 4 = FALSE

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3 years ago
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Step-by-step explanation:

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