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andriy [413]
3 years ago
9

POINT out the correct ANSWER (Free_

Mathematics
2 answers:
svlad2 [7]3 years ago
4 0

Answer:

40...................................

lina2011 [118]3 years ago
4 0

Answer:

35 points because you said so O-O

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How can I solve this? 10+x = 5(1/5x + 2)
pshichka [43]
You use PEMDAS. Start by distributing the terms in the parentheses. The isolate the variables. To do that you subtract x from one side of the equation to the other side. You always do the other operation. If it is adding you subtract, if your multiplying your dividing and the other way around. Then you subtract 10 from each side. This equation has many solution because all the terms cancel out.
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3 years ago
Find the surface of the prism
natta225 [31]

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no se podrías resolverlo tu

6 0
2 years ago
4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10
Andrew [12]

Given the function f(x);

f(x)=-4x^2+4x-1

Evaluating the function f(x+h);

\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}

So;

f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1

Evaluating the second function;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}

simplifying further;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}

Therefore, we have;

undefined

7 0
11 months ago
Calcula la longitud en YARDAS de
tatiyna

Answer:

Las longitudes solicitadas en yardas son:

  • <u>Trayecto A = 109.361 yardas.</u>
  • <u>Trayecto B = 20.231785 yardas.</u>

Step-by-step explanation:

Para hacer la conversión de unidades que requieres en el ejercicio, debes saber que:

  • 1 metro = 1.09361 yardas

Con ese factor de conversión tú puedes hacer reglas de tres para calcular las medidas que requieres. En el caso del trayecto A:

Si:

  • 1 metro = 1.09361 yardas
  • 100 metros = X

Entonces:

  • x=\frac{100m *1.09361yardas}{1m}

Cancelamos metros y obtenemos:

  • x = 100 * 1.09361 yardas
  • <u>x = 109.361 yardas</u>

En este caso, <u>el trayecto A en yardas corresponde a 109.361 yardas</u>. El mismo procedimiento puede aplicarse para el trayecto B:

Si:

  • 1 metro = 1.09361 yardas
  • 18.50 metros = X

Entonces:

  • x = \frac{18.50m*1.09361yardas}{1m}

Cuando se cancelan los metros se obtiene:

  • x = 18.50 * 1.09361 yardas
  • <u>x = 20.231785 yardas</u>

Así, <u>el trayecto B en yardas corresponde a 20.231785 yardas</u>.

4 0
3 years ago
Graph 2 + 3y = 6. Please hurry
vitfil [10]

Answer:

Step-by-step explanation:

5 0
3 years ago
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