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3 years ago

How do you solve literal eqations

Mathematics

1 answer:

Stels [109]3 years ago

5 0

Answer: When given a literal equation, you will often be asked to solve the equation for a

given variable. The goal is to isolate that given variable. The process is the same

process that you use to solve linear equations; the only difference is that you will

be working with a lot more letters, and you may not be able to simplify as much as

you can with linear equations. This packet will hopefully show you the process in a

simple manner so that you will be able to solve literal equations yourself.

Step-by-step explanation:

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Solve:<br> 3x - 9 = 5(x-3)

Viefleur [7K]

Hi,

$3x - 9 = 5(x-3)\\3x - 9 - 5(x-3)= 0\\3x -9 -5x +15 =0\\6-2x=0\\6=2x\\x=3$

Have a good day.

3 0

2 years ago

What is the frequency of the sinusoidal graph ?

disa [49]

Answer:

The frequency of the given sinusoidal graph is 4.

Step-by-step explanation:

The frequency of a sinusoidal graph is the number of cycles it completes in the interval 0 to 2π radians.

From the given sinusoidal graph it is noticed that the the graph complete its one cycle in the interval 0 to $\frac{\pi}{2}$ .

If the complete its one cycle in $\frac{\pi}{2}$ , then the number of cycles completed by the graph in the inteval 0 to 2π is

$\frac{\pi}{2}\times frequency=2\pi$

$frequency=2\pi \times \frac{2}{\pi}$

$frequency=4$

Therefore the frequency of the given sinusoidal graph is 4.

7 0

3 years ago

Mrs. Stern washed

bekas [8.4K]

Answer:

Mrs. Stern washed more

$\frac{7}{20}$ laundry still needs to be washed.

Step-by-step explanation:

Total amount of laundry: $\frac{20}{20}$

$\frac{20}{20} -\frac{2}{5}-\frac{1}{4} =$

$\frac{20}{20} - \frac{8}{20} -\frac{5}{20} =$

$\frac{7}{20}$ of the laundry still needs to be done.

Mrs. Stern washed $\frac{8}{20}$ of the laundry.

Her son washed $\frac{5}{20}$ of the laundry.

Mrs. Stern washed more laundry than her son.

8 0

2 years ago

If 8x=7, what is the value of 5 (x+1/2)

beks73 [17]

X=7/8
So replace X with ^

5 0

2 years ago

Solve 2cos^2x+5cosx+2=0

Nuetrik [128]

$2cos^2x+5cosx+2=0\\
x\in\\
\Delta=b^2-4ac\\
\Delta=9\\
\sqrt{\Delta}=3\\
cosx=1\\
or\\
cosx=-6\\
-6\notin\\$

Then using trygonometric table or a graph we read that:
$cosx=1\Leftrightarrow(x)=0$

Period of cosinus function = 2π
So the last answer is $x=0+2k\pi\\$

6 0

3 years ago