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xxTIMURxx [149]
3 years ago
8

Yesterday, the snow was 2 feet deep in front of Archie’s house. Today, the snow depth dropped to 1.6 feet because the day is so

warm. What is the percent change in the depth of the snow?
The percent change in the depth of snow from yesterday to today is
Mathematics
2 answers:
creativ13 [48]3 years ago
8 0
The correct answer is 20%
2ft. - 1.6ft = 0.4ft.
0.4ft. / 2ft. = 0.2ft
0.2ft x 100% = 20%

jolli1 [7]3 years ago
5 0
Was = 100%
Now = 80%
Difference = 20%
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Find the center and radius of the circle with the equation (x+5)^2+(y-2)^2=25
chubhunter [2.5K]

Answer:The center is (-5,2)

The radius is 5

Step-by-step explanation:

Equation of a circle is:

(x-h)^2+(y-k)^2=r^2

(x+5)^2+(y-2)^2=5^2

Comparing both equations we get :

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3 years ago
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algol [13]

Answer:

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

29.5+1.671\frac{5.2}{\sqrt{59}}=30.63    

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

\bar X = 29.5 represent the sample mean

\mu population mean  

s= 5.2 represent the sample standard deviation

n=59 represent the sample size  

Confidence interval

The confidence interval for the true mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=59-1=58

The Confidence interval is 0.90 or 90%, the significance is \alpha=0.1 and \alpha/2 =0.05, and the critical value is t_{\alpha/2}=1.671

Now we have everything in order to replace into formula (1):

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

29.5+1.671\frac{5.2}{\sqrt{59}}=30.63    

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

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3 years ago
PLSS ANSWER
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Step-by-step explanation:

5 0
3 years ago
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