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xxTIMURxx [149]
4 years ago
8

Yesterday, the snow was 2 feet deep in front of Archie’s house. Today, the snow depth dropped to 1.6 feet because the day is so

warm. What is the percent change in the depth of the snow?
The percent change in the depth of snow from yesterday to today is
Mathematics
2 answers:
creativ13 [48]4 years ago
8 0
The correct answer is 20%
2ft. - 1.6ft = 0.4ft.
0.4ft. / 2ft. = 0.2ft
0.2ft x 100% = 20%

jolli1 [7]4 years ago
5 0
Was = 100%
Now = 80%
Difference = 20%
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Y=2x-4 <br> What is the five ordered pairs and completing the input/output table
kati45 [8]

Answer:

{(0, -4), (1, -2), (2, 0), (3, 2), (4, 4)}

<u>Input values (x)</u> = {0, 1, 2, 3, 4}

<u>Output values (y)</u> = {-4, -2, 0, 2, 4}

Step-by-step explanation:

Given the linear equation, y = 2x - 4, you could practically choose any input value (for x), to have an output value (for y).

If x = 0:

y = 2(0) - 4

y = 0 - 4

y = -4

First ordered pair: y-intercept =  (0, -4)

If x = 1:

y = 2(1) - 4

y= 2 - 4

y = -2

Second ordered pair: (1, -2).

If x = 2:

y = 2(2) - 4

y= 4 - 4

y = 0

Third ordered pair: x-intercept =  (2, 0).

If x = 3:

y = 2(3) - 4

y = 6 - 4

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Fourth ordered pair: (3, 2).

If x = 4:

y = 2(4) - 4

y = 8 - 4

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Fifth ordered pair: (4, 4).

Your input values (x) = {0, 1, 2, 3, 4}

Your output values (y) = {-4, -2, 0, 2, 4}

6 0
3 years ago
You want to place a towel bar that is 24 1/4 centimeters long in the center of a door that is 70 1/3 centimeters wide. How far s
Aleksandr [31]

Answer:

The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

Step-by-step explanation:

Given:

Length of the towel bar = 24\frac14\ cm

Now given length is in mixed fraction we will convert in fraction.

To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.

24\frac14\ cm can be Rewritten as \frac{97}{4}\ cm

Length of the towel bar =  \frac{97}{4}\ cm

Length of the door = 70 \frac13\ cm

70 \frac13\ cm can be Rewritten as \frac{211}{3}\ cm

Length of the door = \frac{211}{3}\ cm

We need to find the distance bar should be place at from each edge of the door.

Solution:

Let the distance of bar from each edge of the door be 'x'.

 So as we placed the towel bar in the center of the door it divides into two i.e. '2x'

Now we can say that;

\frac{97}{4}+2x=\frac{211}{3}\\\\2x=\frac{211}{3}-\frac{97}{4}

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2x=\frac{211\times4}{3\times4}-\frac{97\times3}{4\times3}\\\\\\2x= \frac{844}{12}+\frac{281}{12}

Now denominators are common so we will solve the numerators.

2x =\frac{844-291}{12}\\\\2x=\frac{553}{12}\\\\x=\frac{553}{12\times2} =\frac{553}{24}

Or x=23\frac{1}{24}\ cm

Hence The towel bar should be placed at a distance of 23\frac{1}{24}\ cm from each edge of the door.

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3 years ago
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