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strojnjashka [21]
3 years ago
7

Find the range of the function for the given domain.

Mathematics
2 answers:
slavikrds [6]3 years ago
4 0

Answer:

{-14,-5,-2,10}

Step-by-step explanation:

The given function is

f(x)=3x-5

We need to find the function of the given domain.

The given domain of the function is {-3,0,1,5}.

Substitute x=-3 in the given function.

f(-3)=3(-3)-5\Rightarrow -9-5=-14

Substitute x=0 in the given function.

f(0)=3(0)-5\Rightarrow 0-5=-5

Substitute x=1 in the given function.

f(1)=3(1)-5\Rightarrow 3-5=-2

Substitute x=5 in the given function.

f(5)=3(5)-5\Rightarrow 15-5=10

Therefore, the range of the function for given domain is {-14,-5,-2,10}.

eimsori [14]3 years ago
3 0

You need to evaluate the function at the given points:

\begin{array}{c|c}x&f(x)\\-3&-14\\0&-5\\1&-2\\5&10\end{array}

So, the range is

\{-14,-5,-2,10\}

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The net of a triangular prism is show below.Find the rotal surface area of the triangular prism 4.6,4,5,15
marysya [2.9K]

Answer:

228.4cm²

Step-by-step explanation:

Find the diagram attached

Total surface area of the prism = Ph + 2B

P is the perimeter of the base (triangle)

h is the height of the prism

B is Base area

P = 5cm + 5cm + 4cm

P = 14cm

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B = 1/2 * base * height

B  = 1/2 * 4.6 * 4

B = 4.6 * 2

B = 9.2cm²

Substitute the values into the formula;

Total surface area of the prism = Ph + 2B

Total surface area of the prism = 14(15)+2(9.2)

Total surface area of the prism = 210 + 18.4

Total surface area of the prism = 228.4cm²

Hence the total surface area of the triangular prism is 228.4cm²

7 0
3 years ago
What fraction of a day is 14 hours
Naily [24]
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7 0
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Solve by using the measurements ∠PQR = 90°, ∠QRP = 80°, and r = 15. Round measures of sides to the nearest tenth and measures of
valkas [14]

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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