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DIA [1.3K]
3 years ago
10

7.

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0

Answer:

the new area is 1% smaller.

Step-by-step explanation:

the area of a rectangle is length times breadth.

let's call them a and b

Area = a × b

now, a is increased by 10%. that means it is multiplied by 11/10.

because 100% means the whole thing, 1% means a 1/100th part of the whole. and 10% then means 10 times the 1/100th part of 10 × 1/100 = 10/100 = 1/10

if then simmering increases by 10% it means that it is the original 100% plus 10%.

so, it is 100/100 + 10/100 = 10/10 + 1/10 = 11/10

therefore the new length is

a(new) = a(old)×11/10

in exactly the same way, when the breadth is reduced by 10% we get then

breadth(new) = breadth(old)×9/10

so, Area(new) = a(new)×b(new) = a(old)×11/10 × b(old)×9/10

remember, Area(old) = a(old)×b(old)

so, Area(new) = a(old)×b(old) × 11/10 × 9/10 =

= Area(old) × 11/10 × 9/10 =

= Area(old) × 99/100

that means the new area has lost compared to the old area 1/100th of its size. 1/100th = 1%

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The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
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Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

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Number of altimeters that are not correctly calibrated = 2

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(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

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(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

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(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

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