All categories

2 years ago

7.

Mathematics

1 answer:

Alenkinab [10]2 years ago

4 0

Answer:

the new area is 1% smaller.

Step-by-step explanation:

the area of a rectangle is length times breadth.

let's call them a and b

Area = a × b

now, a is increased by 10%. that means it is multiplied by 11/10.

because 100% means the whole thing, 1% means a 1/100th part of the whole. and 10% then means 10 times the 1/100th part of 10 × 1/100 = 10/100 = 1/10

if then simmering increases by 10% it means that it is the original 100% plus 10%.

so, it is 100/100 + 10/100 = 10/10 + 1/10 = 11/10

therefore the new length is

a(new) = a(old)×11/10

in exactly the same way, when the breadth is reduced by 10% we get then

breadth(new) = breadth(old)×9/10

so, Area(new) = a(new)×b(new) = a(old)×11/10 × b(old)×9/10

remember, Area(old) = a(old)×b(old)

so, Area(new) = a(old)×b(old) × 11/10 × 9/10 =

= Area(old) × 11/10 × 9/10 =

= Area(old) × 99/100

that means the new area has lost compared to the old area 1/100th of its size. 1/100th = 1%

You might be interested in

Determine if the following event is independent or dependent. Ursula went to the market and chose a blue marker from one box of

erastova [34]

Because is likely that the first outcome affected the second one, we can conclude that the events are dependent.

<h3>When two events are independent?</h3>

Two events are independent if the outcome of one can't affect the outcome of the other.

Here, first, she chooses a blue marker from one box and then a yellow one from another, these are the two events.

Now, these are independent or dependent?.

Well, the fact that she chooses a blue marker first, means that she probably would not want to choose another blue marker for the second one. So yes, the first outcome does affect the second outcome, meaning that the events are dependent.

If you want to learn more about dependent and independent events, you can read:

brainly.com/question/1757299

6 0

2 years ago

An experiment is designed to determine the launch angle that will give a projectile the greatest range (make it go the longest d

RideAnS [48]

Test each

if angle is increased, rock will go further
if the angle starts at 0, then increases to 90 degrees (straight up) the rock will go up then bounce off of the launcher going either front or back, but vastly shorter than if it were pointed straight ahead

2nd one
changing angle change the distance
we see that is true

5 0

3 years ago

Read 2 more answers

Multiply 3/sqrt17- sqrt2 by which fraction will produce an equivalent fraction with rational denominator

zzz [600]

Answer:

Step-by-step explanation:

To simplify something that looks like $\frac{\text{whatever}}{\sqrt{a}-\sqrt{b}}$ you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

$\sqrt{a}+\sqrt{b}$ .

If you had $\frac{\text{whatever}}{\sqrt{a}+\sqrt{b}}$ , then you would multiply top and bottom the conjugate of $\sqrt{a}+\sqrt{b}$ which is $\sqrt{a}-\sqrt{b}$ .

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens. The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First: a(a)=a^2

Outer: a(-b)=-ab

Inner: b(a)=ab

Last: b(-b)=-b^2

--------------------------Adding.

a^2-b^2

See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of $\sqrt{17}-\sqrt{2}$ is

$\sqrt{17}+\sqrt{2}$ .

This is the thing we are multiplying and top and bottom.

3 0

3 years ago

Read 2 more answers

Helllpppp!!!!!it is a log equation

Vaselesa [24]

I hope this is right

2log $2log6(2)+3log6(t)+1/2xlog6(y)$

6 0

2 years ago

Explain why the function is discontinuous at the given number

Blizzard [7]

For $f$ to be continuous at $x=5$ , we need to have

$\displaystyle\lim_{x\to5}f(x)=f(5)$

Note that $x\to5$ means that $x\neq5$ , but that $x$ is *approaching* 5. We're told that for $x\neq5$ , we have

$f(x)=\dfrac{x^2-5x}{x^2-25}$

We can write

$\dfrac{x^2-5x}{x^2-25}=\dfrac{x(x-5)}{(x+5)(x-5)}=\dfrac x{x+5}$

and the limit would be

$\displaystyle\lim_{x\to5}\frac x{x+5}=\dfrac5{5+5}=\dfrac5{10}=\dfrac12\neq1=f(5)$

and so $f$ is discontinuous.

5 0

3 years ago