Answer:
12.94%
Step-by-step explanation:
r = 100(1/2)^(d/5) = 100((1/2)^(1/5))^d ≈ 100(.87055)^d
The daily decrease is 1 - 0.87055 = 0.12944 ≈ 12.94%
Given:
Number of passengers seated in the roller coaster = 21
Empty seats = 3
Number of cars in roller coaster = 4 (each with the same number of seats)
To find:
An equation that can be used to determine the number of seats in each car.
Solution:
Let s be the number of seats in each car.
Total number of seats in 4 cars = 4s
Using the given information,
Total number of seats = Occupied seated + Empty seats
= 21 + 3
= 24
Now, the required equation is

Therefore, the required equation is
.
Divide both sides by 4.


Therefore, the number of seats in each car is 6.
Answer:
John is 9 and Olivia is 12
Step-by-step explanation:
12+18= 20
36+ (9x8)= 108
The property illustrated is the Commutative Property
Answer:

Step-by-step explanation:
Given

Required
Determine the solution
Since b is a perfect square, the equation can be expressed as:

Apply difference of two squares:

Split:

Remove brackets:

Make a the subject in both equations

The solution can be represented as:
