Y=-2(x+5)^2-30 In standard form

nexus9112 [7]

I believe you multiple 343 times a hundred and the answer you gt you divide it by 35 and then you get 980?

5 0

3 years ago

1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,

crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

$PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}$

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

$PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111$

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

$PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666$

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

$PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222$

3 0

3 years ago

Let U={x: x is an integer and 2≤x≤10}. In each of the following cases, find A,B and determine whether A⊆B,B⊆A, both or neither:

12345 [234]

A is not a subset of B but B is a subset of A (that is can be found in A) that is B⊆A is correct

<h3>Set theory</h3>

Set is defined as the arrangement of elements. They can be represented using the venn diagram.

Given the following sets

U = {x: x is an integer and 2≤x≤10} = {3, 4, 5, 6, 7, 8, 9}
A = {x: 2x+1>7} = {x > 3}

B={x: x^2>20} = {x >± 20}

From the set, can see that A is not a subset of B but B is a subset of A (that is can be found in A) that is B⊆A is correct

Learn more on sets here: brainly.com/question/13458417

8 0

2 years ago

Find the value of y when x=3<br> y=2x3<br> y=0

MaRussiya [10]

Answer: 54

Why? You need to put 3 in for x so you get
2(3)^3
3 to the third power is 3*3*3 which equals 27
2(27)
Now you must do 2 times 27 and you get 54

Hope this helps

8 0

3 years ago

Please help thank you

matrenka [14]

Answer:

25.9 yd

Step-by-step explanation:

$a^{2}$ + ${b^{2} }$ = $c^{2}$