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3 years ago

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Unpolarized light passes through two ideal Polaroid sheets. 12.3% of the incident light is transmitted. What is the angle betwee

n the transmission axes of the Polaroid sheets?

1 answer:

snow_lady [41]3 years ago

5 0

Answer:

Explanation:

If I be the intensity of original light , after first polarization , its intensity becomes I/2

After second polarization its intensity becomes I/2 X Cos²θ

where θ is the angle between the two polaroids

So I₁ = I/2 Cos²θ

I₁ / I =.5 X Cos²θ = 0.123

Cos²θ = 0.246

θ = 60 degree. Ans

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Answer:

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Explanation:

This is a horizontal shooting problem, so we will use the following equations.

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Where $x(t)$ is the horizontal distance at a time $t$ , $x_{0}$ is the initial horizontal position which in this case will be zero: $x_{0}=0$ . And $v_{0}$ is the initial speed: $v_{0}=2m/s$

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Now, to solve (b) we need the equation for vertical distance:

$y(t)=y_{0}-\frac{1}{2}gt^2$

Where $y(t)$ is the vertical distance at a time $t$ , $y_{0}$ is the initial vertical distance: $y_{0}=10m$ And $g$ is the gravitational acceleration: $g=9.81m/s^2$ }

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$y(0.8)=10m-\frac{1}{2}(9.81m/s^2)(0.8)^2$

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$y(0.8)=6.86m$

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Using $y(t)=y_{0}-\frac{1}{2}gt^2$

if $y(t)=0$

$0=10-\frac{1}{2}gt^2\\-10=-\frac{1}{2}gt^2\\20=gt^2\\\frac{20}{g}=t^2\\ \sqrt{\frac{20}{g}}=t$

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Explanation:

I hope this helps! Have a great day!

Anygays-

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