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tino4ka555 [31]
3 years ago
15

What kind of model is shown below?

Physics
1 answer:
Rudiy273 years ago
7 0
D. a foot model



btw this is a joke right cuz there ain’t no picture lol
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What is the strength of the electric field in a region where the electric potential is constant?
Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx        ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

<em>Therefore, a constant electric potential means that electric field is zero.</em>

4 0
3 years ago
an electrical generator is an important component in a power plant. which best shows the energy transfer diagram for a generator
Evgen [1.6K]

Answer:The answer is B

Explanation:

A generator produces electricity. Energy enters the system (generator) as kinetic energy. It is converted into electrical energy, which can run electrical appliances. Some energy is always wasted as heat and sound. Therefore, Choice B is the best answer.

7 0
3 years ago
Read 2 more answers
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alexandr402 [8]
Option A is the correct answer.
5 0
2 years ago
a surface recieving sound is moved from it original position to a position three times farther away from the source of the sound
Delicious77 [7]
Sound intensity = 1/(r^2)

That is Sound intensity is indirectly proportional to  the distance. Therefore, sound becomes 9 times less intense.
7 0
2 years ago
The patellar tendon attaches to the tibia at a 20 deg angle 3 cm from the axis of rotation at the knee. If the force generated i
gregori [183]

Answer:

the resulting angular acceleration is 15.65 rad/s²

Explanation:

Given the data in the question;

force generated in the patellar tendon F = 400 N

patellar tendon attaches to the tibia at a 20° angle 3 cm( 0.03 m ) from the axis of rotation at the knee.

so Torque produced by the knee will be;

T = F × d⊥

T = 400 N × 0.03 m × sin( 20° )

T = 400 N × 0.03 m × 0.342

T = 4.104 N.m

Now, we determine the moment of inertia of the knee

I = mk²

given that; the lower leg and foot have a combined mass of 4.2kg and a given radius of gyration of 25 cm ( 0.25 m )

we substitute

I = 4.2 kg × ( 0.25 m )²

I = 4.2 kg × 0.0626 m²

I = 0.2625 kg.m²

So from the relation of Moment of inertia, Torque and angular acceleration;

T = I∝

we make angular acceleration ∝, subject of the formula

∝ = T / I

we substitute

∝ = 4.104 / 0.2625

∝ = 15.65 rad/s²

Therefore, the resulting angular acceleration is 15.65 rad/s²

8 0
3 years ago
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