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Doss [256]
3 years ago
6

What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4

Physics
2 answers:
mrs_skeptik [129]3 years ago
5 0

Answer:

x = 2\sqrt 2

Explanation:

Given

Hypotenuse = 4

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

x^2 + x^2 = 4^2 --- i.e. the other legs are equal

So, we have:

2x^2 = 16

Divide both sides by 2

x^2=8

Take square roots of both sides

x = \sqrt 8

Simplify

x = 2\sqrt 2

myrzilka [38]3 years ago
4 0

Answer:

7√2

Explanation:

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The exhaust fan on a typical kitchen stove pulls 600 CFM (cubic feet per minute) through the filter. Given that 1.00 in. = 2.54
zysi [14]

Answer:

0.283\ m^3/s

Explanation:

Given that,

1.00 in = 2.54 cm

We know that,

1 feet = 12 inches

1\ feet =12\times0.0254

1\ feet =0.3048\ m

We calculate the number

We need to converted ft^3/min to m^3/sec

The number required is

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600ft^3/min=0.283\ m^3/s

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4 0
3 years ago
A ball is kicked at an angle of 35° with the ground.a) What should be the initial velocity of the ball so that it hits a target
stiks02 [169]

Answer:

a.18.5 m/s

b.1.98 s

Explanation:

We are given that

\theta=35^{\circ}

a.Let v_0 be the initial velocity of the ball.

Distance,x=30 m

Height,h=1.8 m

v_x=v_0cos\theta=v_0cos35

v_y=v_0sin\theta=v_0sin35

x=v_0cos\theta\times t=v_0cos35\times t

t=\frac{30}{v_0cos35}

h=v_yt-\frac{1}{2}gt^2

Substitute the values

1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2

1.8=30tan35-\frac{6574.6}{v^2_0}

\frac{6574.6}{v^2_0}=21-1.8=19.2

v^2_0=\frac{6574.6}{19.2}

v_0=\sqrt{\frac{6574.6}{19.2}}=18.5 m/s

Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

t=\frac{30}{18.5cos35}

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

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3 years ago
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inessss [21]

Answer: 100

Explanation:

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Oksanka [162]

Answer:

10x5?

Explanation:

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