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Doss [256]
2 years ago
6

What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4

Physics
2 answers:
mrs_skeptik [129]2 years ago
5 0

Answer:

x = 2\sqrt 2

Explanation:

Given

Hypotenuse = 4

Required

Find x

Since the triangle is a 45-45-90 triangle, the following relationship exists

x^2 + x^2 = 4^2 --- i.e. the other legs are equal

So, we have:

2x^2 = 16

Divide both sides by 2

x^2=8

Take square roots of both sides

x = \sqrt 8

Simplify

x = 2\sqrt 2

myrzilka [38]2 years ago
4 0

Answer:

7√2

Explanation:

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How do I do this problem?
Aleks04 [339]

Use Charles Law: V1/T1 = V2/T2

0.30 m^3/27 C = V2/127 C

27V2 = 127 * 0.3

V2= 38.1/27 = 1.4 m^3

5 0
3 years ago
The speed of light will change in which of the following situations?
zhannawk [14.2K]

Answer:

The light moves through glass, then air

3 0
3 years ago
Covert 35000000 miles to meters and show how you got the answer?
Lina20 [59]

Answer:

56327040000 metres

Explanation:

1 mile =

1609.344 metres

35000000 miles = x meters

we represent x by the number of meters which the requested miles maps to

we cross multiply, so 1609.344×35000000 = 1 × x

x =56327040000 metres

8 0
3 years ago
A train travels 76 kilometers in 2 hours and then 54 kilometers in 5 hours .What is the average speed ?
gizmo_the_mogwai [7]
V = d ÷ t --> bc d=vt
V = (76+54)÷(2+5) = 130÷7 = 18.57km/hr
7 0
3 years ago
Unpolarized light with an average intensity of 845 W/m2 moves along the x-axis when it enters a Polarizer A with a vertical tran
horsena [70]

Answer:

θ = 36.2º

Explanation:

When light passes through a polarizer it becomes polarized and if it then passes through a second polarizer, it must comply with Malus's law

         I = I₀ cos² tea

The non-polarized light between the first polarized of this leaves half the intensity, with vertical polarization

          I₁ = I₀ / 2

          I₁ = 845/2

          I₁ = 422.5 W / m²

In this case, the incident light in the second polarizer has an intensity of I₁ = 422.5 W / m² and the light that passes through the polarizer has a value of

I = 275 W / m ²

      Cos² θ = I / I₁

      Cos θ = √ I / I₁

      Cos θ = √ (275 / 422.5)

     Cos θ = 0.80678

     θ = cos⁻¹ 0.80678

     θ = 36.2º

This is the angle between the two polarizers

8 0
3 years ago
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