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jasenka [17]
3 years ago
10

During the month of April, Dora kept track of the bogs she saw in her garden. She saw a ladybug on 23 days of the month. What is

the experimental probability that she will see a ladybug on May 1?
Mathematics
1 answer:
grandymaker [24]3 years ago
8 0
23/30 simplify from here
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Simplify the square root.<br> 6-63
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Answer:

18i\sqrt{x} 7\\

Step-by-step explanation:

the answer is 18i in front if the root square an 7 goes inside it

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3/32 in simplest form
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It is in its simplest form

Step-by-step explanation:

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Find the measure of DC if m
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Answer:

  • B. 132°

Step-by-step explanation:

<u>Find the measure of arc BD</u>

  • m∠A = 1/2(arc BC - arc BD)
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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125
Savatey [412]

we have that

300 + 150 + 75 +...

Let

a1=300\\ a2=150\\ a3=75

we know that

\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50

\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50

so

a(n+1)=an*0.50

Is a geometric sequence

Find the value of a4

a(4)=a3*0.50

a(4)=75*0.50

a(4)=37.5

Find the value of a5

a(5)=a4*0.50

a(5)=37.5*0.50

a(5)=18.75

Find S5

S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25

therefore

the answer is

581.25

Alternative Method

Applying the formula

S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25

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the answer is

581.25

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