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ELEN [110]
3 years ago
12

When performing a benchmarking analysis of a hotel operating statement, which of the following measures of financial comparison

would typically not be used?
Mathematics
1 answer:
Murljashka [212]3 years ago
8 0

Question:

When performing a benchmarking analysis of a hotel operating statement, which of the following measures of financial comparison would typically not be used?

a) Dollar per available room

b) Dollar per occupied room

c) Percent of revenue ( or departmental revenue)

d) Percent or original construction cost

Answer:

d) Percent or original construction cost

Explanation:

<u><em>Benchmarking analysis</em></u>: Benchmarking analysis is a method of comparing organisation or business process and performance with other companies to  meet the industry best practices. This is a performance measure used in determining the quality, time and cost.

<u><em>Operating statement:</em></u> This is a financial statement that contains the business activity results for a specific period time, this entails the  income statement, earnings report, profit and loss statement. This statement is also known as profit and loss statement.

<em>Therefore from the list of options provided above, Percent or original construction cost would typically not be used as a measure of financial comparison when performing a benchmarking analysis of a hotel operating statement.</em>

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The lifespan, in years, of a certain computer is exponentially distributed. The probability that its lifespan exceeds four years
kompoz [17]

Answer:

The correct answer is "0.300993e^{-0.300993x}".

Step-by-step explanation:

According to the question,

⇒ P(x>4)=0.3

We know that,

⇒ P(X > x) = e^{(-\lambda\times x)}

⇒     e^{(-\lambda\times 4)} = 0.3

∵ \lambda = 0.300993

Now,

⇒ f(x) = \lambda e^{-\lambda x}

By putting the value, we get

           =0.300993e^{-0.300993x}

3 0
3 years ago
A mobile company charges a fixed rate of x cents per minute for the first 120 minutes of talk time and another rate of y cents p
patriot [66]

Answer:

$21.2

Step-by-step explanation:

From the problem given, we express them as algebra so that we can easily solve;

    the total charge on a call greater than 120min is given as;

   120x + y(n - 120) = total cost of call

where n is the number of minutes which is greater than 120;

  •   Ethan paid $26.80  for 175 mins

  n = 175min here;

      120x + y(175 - 120) = 26.80

       120x + 55y = 26.80 ----- (I)

  • $32.40 for 210 minutes

      n = 210min

       120x + y(210 - 120) = 32.4

       120x + 90y = 32.4 ----- (II)

Now let us solve both equations for y and x;

      120x + 55y = 26.80 ----- (I)

     120x + 90y = 32.4 ----- (II)

subtract the two equations;

             90y - 55y = 32.4 - 26.8

                  35y = 5.6

                       y = \frac{5.6}{35}  = 0.16cents

then x;

       120x = 26.8 - 55y from equation I

       120x = 26.8 - 55(0.16)

       120x = 18

            x = \frac{18}{120}  = 0.15cents

Find the cost of 140min of talk time;

  n =140min;

      =  120(0.15) + 0.16(140 - 120)

      = 18 + 0.16(20)

      = 18 + 3.2

      = $21.2

4 0
4 years ago
2) Eight is 5 less than<br> twice the number R.
posledela

Answer:

8-5 times R

Step-by-step explanation:

you subtract 8-5 to get that answer and then you do less than twice the number r i think this is correct hope it helps :)

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