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2 years ago

What is the area of the polygon ?

Mathematics

1 answer:

Alona [7]2 years ago

6 0

Answer:

To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothem. Here is what it means: Perimeter = the sum of the lengths of all the sides.

Step-by-step explanation:

Could i have branliest please

if you didnt mean this you forgot the screenshot

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Hya think of a number "m" . She square it, add "y" to the answer and then subtract 7 from it. The final answer is "A". 1) Derive

Bond [772]

<h2>Solution (1) :</h2>

Given, to find A we have to :

square m
Add y to m²
Subtract 7 from m² + y

From the question, the following equation can be formed :

$=\tt A = {m}^{2} + y - 7$

Therefore, the formula for finding A = m² + y - 7

<h2>Solution (2) :</h2>

The value of A we can derive from the formula is :

$=\tt A = {m}^{2} + y - 7$

Value of m = 3 (given)

Which means :

$=\tt A = {3}^{2} + y - 7$

$=\tt \: A = 9 + y - 7$

$=\tt A = 9 - 7 + y$

$\color{plum} =\tt A = 2 + y$

Thus, the value of A = 2+y

Therefore, the value of A = 2+y

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2 years ago

Latesha buys some tennis balls at $1 each and rackets at $12 each for her PE class. She buys twice as many balls as rackets. She

marysya [2.9K]

I would go with A it makes most sense to me .

3 0

3 years ago

Can sombody please confirm me the formula for SA(surface area) of a triangular prism. please.

mote1985 [20]

$bh + l(s_1 + s_2 + s_3)$
b = base length (of triangle)
h = height of triangle
s = side length of triangle
l = length of rectangle

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3 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$