lateral surface area of this cylinder is 1584/7 or 226.28...cm square.
First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps<span />
Answer:No Matt's calculation is not correct.
Step-by-step explanation:
We have to multiply by the number of the area.If it is 4 inches we multiply by 4
15 x 4 =60
A=4 inches squared
A=LxW (length x width )
so you can say that:
Matt is incorrect because He skipped the step of multiplying 2 by 2 in the formula which is where we get 4 from.
Answer:
9
Step-by-step explanation:
UT^2 = UV * UW
6^2 = (x - 7)(x - 7 + 5)
36 = (x - 7)(x - 2)
36 = x^2 - 2x - 7x + 14
x^2 - 9x - 22 = 0
(x - 11)(x + 2) = 0
x - 11 = 0 or x + 2 = 0
x = 11
UW = x - 7 + 5
UW = 11 - 7 + 5
UW = 9