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Ilia_Sergeevich [38]
3 years ago
8

Find the values of X and Y

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0
They are vertical angles so you need to make the following equal

7y=5y+36 and 3x-21=2x+4

Solve for y and then x

7y=5y+36

Subtract 5y on both sides to get

2y=36

Then divide by 2 on both sides to Get y=18

For 3x-21=2x+4,

Subtract 2x on both sides to obtain

x-21=4

Then add 21 to both sides to get

x=25

Hope this helps!! Mark as brainliest!!!
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AnnZ [28]
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6 0
3 years ago
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Has to be turned in soon at 9:00 it's 7:50
disa [49]

Answer:

A

Step-by-step explanation:

b must always be greater than 0 since 12b-15 must always be greater than 21. You can simplify the ineqaulity to see things easier; 12b>36. Again, this ineqaulity can be simplified; b>3. A is the closest answer here, but there should be an open interval at 3 for A to be correct.

7 0
2 years ago
X^2+x-2/1-x^2 ÷ 2x^2-6x-20/x^2-4x-5
ad-work [718]
<span>X^2+x-2/1-x^2 ÷ 2x^2-6x-20/x^2-4x-5

   (x + 2)(x - 1)           (x - 5)(x + 1)
= ------------------- *  ---------------------
   (1 + x)(1- x)           2(x + 2)(x - 5)

</span>    (x - 1)        
= ----------
   2(1- x)    

    - (1 - x)        
= -------------
     2(1 - x)    

= -1/2

answer
-1/2 
   
7 0
3 years ago
Drag each interval to a box to show if the function shown is increasing, decreasing, or
scoundrel [369]

Answer:

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8 0
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lesya [120]

Answer:

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Solution :

By Congruent rule Side angle side : In triangle 1 and triangle 3 are congruent by side angle side .

Therefore, triangle 1 and triangle 3.

7 0
3 years ago
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