Find the values of X and Y

Mathematics

1 answer:

Nadya [2.5K]3 years ago

4 0

They are vertical angles so you need to make the following equal

7y=5y+36 and 3x-21=2x+4

Solve for y and then x

7y=5y+36

Subtract 5y on both sides to get

2y=36

Then divide by 2 on both sides to Get y=18

For 3x-21=2x+4,

Subtract 2x on both sides to obtain

x-21=4

Then add 21 to both sides to get

x=25

Hope this helps!! Mark as brainliest!!!

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andrew-mc [135]

$\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }$

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Write the divide fraction horizontally:
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$= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}$

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Factorise the numerators and denominators when possible:
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$= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}$

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Convert the divide fraction to multiplication fraction
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$= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}$

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Cancel the factors
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$= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}$

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Combine to single fraction
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$= \dfrac{1}{4(x+2)^2}$

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