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Tamiku [17]
2 years ago
14

A 1/4 mile long suspension bridge is being planned which will require 16 miles of 150 strand (150 wires twisted ) cable to be pl

aced. What is the minimum (ignoring length for twisting) length in km of wire the cable manufacturer needs to have to produce the cable?
Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
8 0

Answer:

out of all of them multimode cables is the best answer

Step-by-step explanation:

You might be interested in
Sam has a rectangular field whose length and breadth are in the ratio 8:7. He wants to fence the field with bamboo to make it an
USPshnik [31]

Answer:

Length = 200 m

Breadth = 175 m

Step-by-step explanation:

Perimeter of the rectangular field = Total cost ÷ rate per metre

                                                        = 12000 ÷ 16

                                                        = 750 m

Length : breadth = 8 : 7

Length = 8x

Breadth = 7x

Perimeter = 750

2*(length + breadth) = 750

2*(8x + 7x) = 750

2* 15x = 750

  30x = 750

      x = 750/30

x = 25

Length = 8x = 8*25 = 200 m

Breadth = 7*25 = 175 m

8 0
2 years ago
ᗯᕼᗩT TᗯO ᗪEᑕIᗰᗩᒪ TᕼᗩT Iᔕ EᑫᑌIᐯᗩᒪEᑎT ᖇI 5.300
kow [346]
5.3 or 5.30 it doesn't matter how many 0's you add
5 0
3 years ago
Read 2 more answers
Solve. [{-9 + x}]<br> ----------- = 3<br> 8
qwelly [4]
-9+x=38
+9. +9
x=47 dats all
6 0
3 years ago
Give me an example of an irrational number that is greater than 10
Pavel [41]

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of \dfrac{p}{q}, where, q\neq 0, p,q are integers.

For example: \sqrt{2}\sqrt{3},\pi, 1.263689...,etc..

We know that square of 10 is 100. So, square root of any prime number is  an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number =\sqrt{101}

Therefore, \sqrt{101} is an irrational number that is greater than 10.

5 0
3 years ago
11 Pause
muminat

Answer:

Step-by-step explanation:

Given that:

Batting average = 0.25 after 160 times at bat;

Batting Average = Number of hits / number of times at bat

0.25 = number of hits / 160

Number of hits = 0.25 * 160 = 40

He want batting average to improve to 0.333 ; if he makes hit the next x times at bat ; number of hits is needed to improve batting average

Hence,

New average = number of hits / number of times at bat

0.333 = (number of hits + x) / (160 + x)

0.333 = (40 + x) / (160 + x)

6 0
3 years ago
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