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antiseptic1488 [7]
3 years ago
12

Choose the equation below that represents the line passing though the point(-5, 1) with a slope of 2/3

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0
Y=2/3x+7/3 is an equation that passes through the point (-5,1) with a slope of 2/3
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2x^3/3y equivalent expressions
ELEN [110]
ت &:$:$$:٧:٧٣٧٣٨٧٣(:(نيjdjsisvshsisbsushvzhdd
3 0
2 years ago
Marsha's class is planting 120 trees as part of a community volunteer project. The class plants pine trees and oak trees in a ra
Ivanshal [37]

Answer:

pine:oak=3:1

pine=3/4*120

pine=90 trees

Step-by-step explanation:

6 0
3 years ago
PLZ help me super really really fast
maria [59]

Answer:

A. 3 cm

Step-by-step explanation:

The smallest face has the sides 4 cm and 8 cm. If the water is 4 cm from its top, then the height of the water is 16-4=12 cm and the volume of the water is

V_{water}=4\cdot 8\cdot 12=384\ cm^3

The largest face has the sides 8 cm and 16 cm. If the container is placed on its largest face, then the volume of the water is

V_{water}=8\cdot 16\cdot h \ cm^3,

where h is the height of the water.

Equate volumes of the water:

8\cdot 16\cdot h=384\\ \\h=\dfrac{384}{8\cdot 16}=3\ cm

Therefore, the water is 3 cm from the bottom.

4 0
3 years ago
Solve |2x-5|=4 pleasee
8090 [49]

Answer:

x = 1/2 and x = 9/2

Step-by-step explanation:

To solve this equation: |2x-5|=4 we need two evaluate two cases:

|2x-5| = 2x-5 when x>5/2 ✅

|2x-5| = -2x+5 when x<5/2✅

Then, if x>5/2:

2x-5 = 4 ➡ x = 9/2

Then, if x>5/2:

-2x+5 = 4 ➡ x = 1/2

Then, the two solutions are:  x = 1/2 and x = 9/2

3 0
3 years ago
Read 2 more answers
Rosters Chicken advertises​ "lite" chicken with​ 30% fewer calories than standard chicken. When the process for​ "lite" chicken
PilotLPTM [1.2K]

Answer:

UCL (x bar) =  424

LCL (x bar) =  376

Step-by-step explanation:

Given:

Average calories contained, μ = 400

Standard deviation, σ  = 30 calories

Sample size, n = 25

a) UCL (x bar) = \mu+\frac{4\sigma}{\sqrt{n}}

On substituting the respective values, we get

UCL (x bar) = 400+\frac{4\times30}{\sqrt{25}}

or

UCL (x bar) =  424

Similarly,

LCL (x bar) =  \mu-\frac{4\sigma}{\sqrt{n}}

On substituting the respective values, we get

LCL (x bar) = 400-\frac{4\times30}{\sqrt{25}}

or

LCL (x bar) =  376

4 0
3 years ago
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