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Maslowich
4 years ago
14

Version A

Mathematics
1 answer:
trapecia [35]4 years ago
3 0
The answer should be c
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Halle la ecuación del eje x y la ecuación del eje y, usando dos puntos que se encuentren sobre los mismos.
lisov135 [29]

Una linea recta ( cualquier eje coordenado es una línea recta) queda definida si se conocen dos puntos que están sobre ella.

Solución:

Ecuación del eje x      y = 0

Ecuación del eje y      x = 0

Para darle respuesta a la pregunta podemos seguir el siguiente procedimiento:

  • Escogemos dos puntos arbitrarios sobre el eje x, por ejemplo

P ( 2 ; 0 )  y Q ( 5 ; 0 )         ( todos los puntos sobre el eje x tienen coordenada y = 0.

Según la cual  m = (y₂ - y₁)/ ( x₂ - x₁ )    m = 0

  • Usamos la ecuación pendiente-Intercepto

y = m×x + b         donde m es la pendiente y b el intercepto con el eje y

y entonces tenemos:

  • m = 0    b ( 0 ; 0 )
  • Por sustitución en la ecuación pendiente-intercepto

y = 0

Procediendo de forma similar obtendremos la ecuación del eje y

P´( 0 ; 4 )     Q´( 0 : 8 ) entonces

y = m×x + b

En este caso, la pendiente no es definida ( tang 90° ) y b es de nuevo el punto b ( 0 ; 0).

A partir de  que todos y cada uno de los puntos sobre el eje y son  de valor 0 para x, concluímos que  ecuación del eje y es

x = 0

Enlaces de interés:brainly.com/question/21135669?

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\bf \stackrel{f(x)}{y}=x^2-6\qquad inverse\implies \boxed{x}=\boxed{y}^2-6
\\\\\\
x+6=y^2\implies \sqrt{x+6}=\stackrel{f^{-1}(x)}{y}
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