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babunello [35]
3 years ago
5

If i can get 6 poland spring water 3-liter for $6. How much would it be if i get 3 poland water?

Mathematics
1 answer:
Blababa [14]3 years ago
6 0

Answer:

$3

if we wanted to find how much 1 bottle would cost we would do 6/6=1 and from that we now know that 1 bottle of water costs $1 so if we times that by 3 to find out how much 3 bottles will cost we get $3.

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For what value of x will 55 and x have the mean (average) as 67
AlekseyPX
If (55 + x)/2 is to be 67, then 55+x = 2*67, so x = 2*67 - 55 = 79
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How many times greater is the value of the 3 in 4,367 than the value of the 3 in 39?​
Lesechka [4]

Answer: Roughly 111.97

Step-by-step explanation:

1. 39 divided by 3 is 13.  

2. 4367 divided by 3 is not evenly distributed. Rounding, it would work out to be roughly 1455.66 

3. 1455.66 divided by 13 is roughly 111.97 (Again, this does not distribute evenly)

4. To check your work, multiply 111.97 times 13 and you should get somewhere around 1455.66 which is (4367 divided by 3).

Hopefully this helps! Feel free to mark brainliest! :)

8 0
3 years ago
If a sprinkler waters 1 over 20 of a lawn in 1 over 5 of an hour, how much time will it take to water the entire lawn?
Genrish500 [490]
5 hours bc my math add ups
7 0
2 years ago
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A company produces 4.56 times 10 Superscript 3 light bulbs each week. Written in scientific notation, which is the best estimate
artcher [175]
Socratic said
(C) 4.5 times 10 Superscript 6 light bulbs
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3 years ago
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The average daily volume of a computer stock in 2011 was million​ shares, according to a reliable source. A stock analyst believ
igomit [66]

Complete question :

The average daily volume of a computer stock in 2011 was p = 35.1 million shares, according to a reliable source. A stock analyst believes that the stock volume in 2014 is different from the 2011 level. Based on a random sample of 40 trading days in 2014, he finds the sample mean to be 30.9 million shares, with a standard deviation of s = 11.8 million shares. Test the hypotheses by constructing a 95% confidence interval. Complete parts (a) through (c) below. State the hypotheses for the test. Construct a 95% confidence interval about the sample mean of stocks traded in 2014.

Answer:

H0 : μ = 35.1 ;

H1 : μ < 35.1 ;

(26.488 ; 35.312)

Step-by-step explanation:

The hypothesis :

H0 : μ = 35.1

H1 : μ < 35.1

The confidence interval :

Xbar ± Margin of error

Xbar = 30.9

Margin of Error = Zcritical * s/sqrt(n)

Zcritical at 95% = 1.96

Margin of Error = 1.96 * (11.8/sqrt(40))

Margin of Error = 4.412

Lower boundary :

30.9 - 4.412 = 26.488

Upper boundary :

30.9 + 4.412 = 35.312

Confidence interval = (26.488 ; 35.312)

Since the population mean value exists within the interval, the we fail to reject the Null.

5 0
2 years ago
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