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bixtya [17]
3 years ago
7

Graph the piecewise function.

Mathematics
1 answer:
Valentin [98]3 years ago
6 0

Answer:

Y=32

Step-by-step explanation:

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Please help ( 20 points )
VashaNatasha [74]

Answer:

1+pi/2, 5/2, square root of 12-1, 2.25. Let me know if this is correct!


Step-by-step explanation:


7 0
3 years ago
A survey question revealed that at a particular college 87 percent of students worked at least sometime during their undergradua
Elanso [62]

Answer:

The correct option is A. 198 degrees

Step-by-step explanation:

Consider the provided information.

87 percent of students worked at least sometime during their undergraduate career and 13 percent did not work at all.

Another question showed that 32 percent of the students worked throughout their undergraduate career.

87 percent  of the students worked at least sometime during the college. Out of them 32% worked throughout the college.

Therefore, the students who worked sometime during their undergraduate career, but not throughout are:

(87-32)% = 55% .

As we know the angle measure in circle  is 360 degrees.

55% of 360° is:

\frac{55}{100}\times360= 198

Hence, the measure of central angle would be 198 degrees

Therefore, the correct option is A. 198 degrees

8 0
3 years ago
HELP!!!!!!!Choose the graph that matches the following system of equations:
PolarNik [594]
The last one. And I did answer for you too.

4 0
3 years ago
Clara ate 1/8 of the pie Jacob ate 1/4 how much of the pie did they ate
nika2105 [10]
They ate 3/8 of the pie because 1/4=2/8 .and 1/8+2/8=3/8. Hope this helps
5 0
3 years ago
Read 2 more answers
During a flu epidemic, 35% of the school's students have the flu. Of those with the flu, 90% have high
frutty [35]

Answer: 0.8015

Step-by-step explanation:

Let F= event that a person has flu

H= event that person has a high temperature.

As per given,

P(F) =0.35

Then P(F')= 1- 0.35= 0.65               [Total probability= 1]

P(H | F) = 0.90

P(H|F') = 0.12

By Bayes theorem, we have

P(F|H)=\dfrac{P(F)\timesP(H|F)}{P(F)\timesP(H|F)+P(F')\timesP(H|F')}\\\\=\dfrac{0.35\times0.90}{0.35\times0.90+0.65\times0.12}\\\\=\dfrac{0.315}{0.315+0.078}\approx0.8015

Required probability = 0.8015

8 0
3 years ago
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